How many mL of 75% alcohol should be mixed with 10% of 1000 cc alcohol to prepare 30% of 500 mL alcohol solution? a. 346.16 mL b
. 234.43 mL c. 153.84 mL d. 121.12 mL e.
1 answer:
Answer:
C. 153.84 mL
Step-by-step explanation:
Let's say x is the volume of 75% solution and y is the volume of 10% solution.
Sum of the volumes:
x + y = 500
Sum of the alcohol amounts:
0.75x + 0.10y = 0.30(500)
0.75x + 0.10y = 150
Solve the system of equations using either substitution or elimination. I'll use substitution.
y = 500 - x
0.75x + 0.10 (500 - x) = 150
0.75x + 50 - 0.10x = 150
0.65x = 100
x = 153.84
You need 153.84 mL of 75% solution.
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