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3 years ago

Which statement about these two triangles is true

Mathematics

2 answers:

klemol [59]3 years ago

8 0

Option A is true...
A).triangle ABC is similar to the triangle FDE becoz...AB/FD=AC/FE.

lana66690 [7]3 years ago

5 0

Answer:

Option A. is the correct option.

Step-by-step explanation:

By the theorem of similar triangles, when two triangles are similar their corresponding sides will be in the same ratio.

In ΔABC and ΔDEF

$\frac{AB}{FD}=\frac{AC}{FE}=\frac{5}{10}=\frac{1}{2}$

So, these two triangles will be similar.

Option A. ΔABC and ΔDEF are similar because $\frac{AB}{FD}=\frac{AC}{FE}$

You might be interested in

If 35% of a number is 21 and 90% of the same number is 54, find 55% of that number.

inn [45]

Answer:

Step-by-step explanation:

The number is 60:

Divide the amount and decimal of the percentage to be extracted

Case 1

$\frac{21}{0.35} =60$

Case 2

$\frac{54}{0.9} =60$

Now the 55% of this number is:

$60(0.55)=33$

Hope this helps

4 0

2 years ago

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago

Please help me!! I'm confused I am not sure what the answer is?

galina1969 [7]

Answer:

my best guess is 2/13 because there are 2 red kings in the deck. I got the 13 because there are 13 different suits

4 0

3 years ago

Find the values of the six trigonometric functions for angle G.<br>

VLD [36.1K]

Answer:

I don't know if it's just my screen or something I can't make out the numbers in the picture it's too fuzzy

8 0

3 years ago

Read 2 more answers

A triangle has side lengths of ( 4h + 2k) centimeters, (9h + 4m) centimeters, and (2m - k) centimeters. Which expression represe

enot [183]

Answer:

P = (13h+k+6m) cm

Step-by-step explanation:

Given that,

The side lengths of a triangle are :

(4h + 2k) cm, (9h + 4m) cm, and (2m - k) cm

We need to find the perimeter of the triangle.

We know that,

Perimeter = sum of all sides

So,

P = (4h + 2k)+(9h + 4m)+(2m - k)

= (4h+9h)+(2k-k)+(4m+2m)

= 13h+k+6m

Hence, the perimeter of the triangle is (13h+k+6m) cm.

4 0

2 years ago