The correct answer is 4 ( 6x - 1 )
I beleive c.....if I am wromng that sucks
System of equations:
The intersection point for this is <em>(4,11)</em>.
The answer is 2.625$ rounded up to 2.63$
Answer:
let p = cost of 1 plain wrapping paper
let h = cost of 1 shiny rolls wrapping paper
Write an equation for each statement,
" Eugene sold 3 rolls of plain wrapping paper and 11 rolls of shiny wrapping paper for a total of $168 "
<em>3</em><em>p</em><em> </em><em>+</em><em> </em><em>1</em><em>1</em><em>h</em><em> </em><em>=</em><em> </em><em>$</em><em>1</em><em>6</em><em>8</em><em> </em>
<em>Jill </em><em> sold </em><em>1</em><em>0</em><em> </em><em> rolls of plain wrapping paper and 1</em><em>1</em><em> </em><em>rolls</em><em> of </em><em>shiny </em><em> wrapping paper for a total of </em><em>$</em><em>2</em><em>5</em><em>2</em><em>."</em>
<em>1</em><em>0</em><em>p + 1</em><em>1</em><em>h = </em><em>$</em><em>2</em><em>5</em><em>2</em><em> </em>
Use elimination here,
10p + 11h = $252
3p + 11h = $168
subtraction eliminates h, find p
7p = $84
p = 84/7
p = $12 for wrap of plain paper
Find h using the 1st original equation
3(12) + 11h = 168
36+ 11h = 168
11h = 168 - 36
11h = 132
h = 132/11
h = $12 for shiny wrapping paper
Therefore each plain wrapping paper costs $12 and each shiny wrapping paper costs same $12 !