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valina [46]
3 years ago
10

Can somebody help me with this please

Mathematics
2 answers:
insens350 [35]3 years ago
5 0
For Vocabulary, I am going to include a photo.

Addend is in the correct slot, but Sum needs to be moved.

I will also include a picture of a Placement chart.

1: 39
2: 15
3: 11

Hitman42 [59]3 years ago
3 0
Eleven is the sum. Add end is 7 and the ones is 4
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#6, #7, and #10 please:)
scoundrel [369]
All given xd ur welcome so ez
3 0
2 years ago
Solve the following equation by completing the square. 3x^2-3x-5=13
mr Goodwill [35]

we'll start off by grouping some

\bf 3x^2-3x-5=13\implies (3x^2-3x)-5=13\implies 3(x^2-x)-5=13 \\\\\\ 3(x^2-x)=18\implies (x^2-x)=\cfrac{18}{3}\implies (x^2-x)=6\implies (x^2-x+~?^2)=6

so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}

so, there's our fellow, however, let's recall that all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add (1/2)², we also have to subtract (1/2)²

\bf \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2-\left[ \cfrac{1}{2} \right]^2 \right)=6\implies \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2 \right)-\left[ \cfrac{1}{2} \right]^2=6 \\\\\\ \left(x-\cfrac{1}{2} \right)^2=6+\cfrac{1}{4}\implies \left(x-\cfrac{1}{2} \right)^2=\cfrac{25}{4}\implies x-\cfrac{1}{2}=\sqrt{\cfrac{25}{4}} \\\\\\ x-\cfrac{1}{2}=\cfrac{\sqrt{25}}{\sqrt{4}}\implies x-\cfrac{1}{2}=\cfrac{5}{2}\implies x=\cfrac{5}{2}+\cfrac{1}{2}\implies x=\cfrac{6}{2}\implies \boxed{x=3}

6 0
3 years ago
You and a friend play a game where you each toss a balanced coin. If the upper faces on the coins are both tails, you win $1; if
dsp73

Answer:

Step-by-step explanation:

Given that you and a friend play a game where you each toss a balanced coin.

If the upper faces on the coins are both tails, you win $1;

if the faces are both heads, you win $2;

if the coins do not match (one shows a head, the other a tail), you lose $1 (win (−$1)).

Let Y be the amount won

Then Y can take values as 1,2 and -1

P(Y=1) =P(TT) = 0.25\\P(Y=2) = P(HH) = 0.25\\P(Y=-1) = P(HT)+P(TH) = 0.5

The above is the probability distribution for Y.

6 0
3 years ago
Maria is asked to write down a prime number between 10 and 20 she writes down 17 is she right explain your answer​
Wittaler [7]

Answer:

YES

Step-by-step explanation:

PRIME NUMBER BETWEEN 10 & 20 ARE 11,13,17,19-four

5 0
2 years ago
Read 2 more answers
Rupert buys a bicycle with a marked price of £ 12500.He gets a rebate of 10% on it. After getting
yarga [219]

Answer:

£ 12,150

Step-by-step explanation:

Marked price of bicycle = £ 12500

Rebate = 10%

Amount of rebate = 12500*10/100 = £1250

Rebated price = 12500 - 1250 = £ 11,250

Tax = 8%

Amount of tax = 11250*8/100 = £ 900

Total amount paid for bicycle = Rebated price + amount of tax

= £ 11,250 + £ 900

= £ 12,150

4 0
3 years ago
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