Hello there!
So there are two separate problems: 9 * (11-4) and 3 * (11-4). To find the value for each expression, use order of operations. We'll solve what's in the parenthesis before multiplying that value by the other number. 11-4 is 7. 7 * 9 is 63. 11-4 is 7. 7 * 3 is 21. You can divide 63 by 21 to get 3. This means that 9 * (11 - 4) is three times as much as 3 *(11 - 4). Even just by looking at the problem, the expression in the parenthesis is the same thing, but the front numbers are different. 9 is three times as much as 3. The answer is A.
For a set to be a function, there can be no repeating x-values. Therefore, the answer is (-4,5), because the input value "-4" has two different output values.
Answer:
78
Step-by-step explanation:
mmmionnbuyffytcvfgh ftvtkyugh gvhgjyh,guv ffghtgvj
Answer:
C
Step-by-step explanation:
Given
![\left[\begin{array}{ccc}-2&3\\2&4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%263%5C%5C2%264%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}3&1\\-1&2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%5C%5C-1%262%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Add corresponding elements to obtain the sum, that is
= ![\left[\begin{array}{ccc}-2+3&3+1\\2-1&4+2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%2B3%263%2B1%5C%5C2-1%264%2B2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}1&4\\1&6\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%5C%5C1%266%5C%5C%5Cend%7Barray%7D%5Cright%5D)
→ C
