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Alborosie
3 years ago
8

The volume code of a cube is given by s to the third power, where s is this side length of the cube. What is the difference of t

he volumes of two cubes with sides lengths of 5 meters and 4 meters
Mathematics
2 answers:
yKpoI14uk [10]3 years ago
6 0

Answer:

61 m^3

Step-by-step explanation:

The difference in volume is (5 m)^3 - (4 m)^3, or (125 - 64) m^3, or

61 m^3

zysi [14]3 years ago
6 0

Answer:

61

Step-by-step explanation:

5³-4³=61

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3 years ago
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Jennifer has 4/5 as many oictures on her camera as luisa does. Jennifer has 28 pictures on her camera. How many pictures do Jenn
spayn [35]
Answer=63 pictures

Jennifer=4/5*Luisa

Jennifer=28
Substitute '28' for Jennifer

28=4/5*Luisa
divide both sides by 4/5
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35+28=63
8 0
3 years ago
An isosceles right triangle has a hypotenuse that measures 4√2 cm. What is the area of the triangle?
torisob [31]

Answer:

8 cm^2

Step-by-step explanation:

If the triangle is isosceles the sides are the same

Let the sides be x

We know that we can use the Pythagorean theorem

a^2+b^2 = c^2 where a and b are the sides and c is the hypotenuse

x^2+x^2 = (4 sqrt(2))^2

2x^2 =16(2)

2x^2 = 32

Divide by 2

2x^2/ 32/2

x^2 = 16

Taking the square root of each side

sqrt(x^2) = sqrt(16)

x = 4

The area of the triangle is

A =1/2 bh

A = 1/2 (4) (4)

A = 1/2(16)

A = 8

4 0
3 years ago
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If the ratio of the radii of two spheres is 6 : 5, what is the ratio of the surface areas of the two spheres?
Veseljchak [2.6K]
Answer: Choice C) 36:25

To get this answer, we simply square each piece of the original ratio 6:5
6^2 = 36
5^2 = 25

Think of two squares where one has a side length of 6 and the other of 5. The ratio of the sides is 6:5. The areas of the two squares are 36 and 25 as mentioned above. So the ratio is 36:25. This idea can be applied to any surface area or area in general. It doesn't have to be two squares. The reason why we can apply this to any general shape is because we can break up the shape into small squares to get a rough approximation. The more squares we use, the better the approximation.
7 0
3 years ago
Write the standard equation for the circle 30. Center (2,7), r=4. 31. Center (-6,-8), that passes treough (0,0)
Salsk061 [2.6K]
The standard equation of the circle is:

(x-h)^2+(y-k)^2=r^2 where (h,k) it the center of the circle and r is the radius...

so

30.

(x-2)^2+(y-7)^2=16

31.

We need to find the radius...(I'll just use the Pythagorean Theorem)

r^2=6^2+8^2

r^2=36+64

r^2=100  (so the radius is 10) and its center is (-6,-8) so

(x+6)^2+(y+8)^2=100
3 0
4 years ago
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