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worty [1.4K]
3 years ago
9

Can someone help again please

Mathematics
2 answers:
Irina-Kira [14]3 years ago
8 0

Answer:

192km^2

Step-by-step explanation:

Well there are 5 surfaces

1) The back one

10km*6km=60km^2

2) the square

(6km)^2=36km^2

3) the two triangles

2(6km*8km/2)=48km^2

4) the front one

6km*8km=48km^2

add all up and get

192km^2

neonofarm [45]3 years ago
4 0

Answer: 192 square kilometers

Step-by-step explanation:

Two triangular Sides A=bh/2 8×6/2=24

So add two of them. : 48

Back side 10 × 6 = 60

Top 6×6=36

Front 6×8=48

Total: 48+60+36+48=192

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A random sample of bolts is taken from inventory, and their lengths are measured. The average length in the sample is 5.3 inches
LekaFEV [45]

Answer:

L_x=5.3 inches

Step-by-step explanation:

Average length \=x =5.3 inches

Standard deviation \sigma=0.2 inches

Sample size n=50

Generally The point estimate for the mean length of all bolts in inventory is

L_x= \=x

L_x=5.3 inches

3 0
3 years ago
A horticulturist working for a large plant nursery is conducting experiments on the growth rate of a new shrub. Based on previou
valkas [14]

Answer:

t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771    

The degrees of freedom are given by:

df=n-1=48-1=47  

And the p value would be:

p_v =P(t_{(47)}    

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

Step-by-step explanation:

Information given

\bar X=1.8 represent the sample mean for the growth

s=0.5 represent the sample standard deviation    

n=48 sample size    

\mu_o =2 represent the value that we want to compare

\alpha=0.01 represent the significance level

t would represent the statistic    

p_v represent the p value

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 2cm per week, the system of hypothesis are :    

Null hypothesis:\mu \geq 2    

Alternative hypothesis:\mu < 2    

Since we don't know the population deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

Replacing the info given we got:

t=\frac{1.8-2}{\frac{0.5}{\sqrt{48}}}=-2.771    

The degrees of freedom are given by:

df=n-1=48-1=47  

And the p value would be:

p_v =P(t_{(47)}    

Since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case for the growth rate is less than 2cm per week

6 0
3 years ago
Draw an area model. Then, solve using the standard algorithm. 27x36
Ganezh [65]
Answer is 972 so i will like for you to make sure

3 0
3 years ago
If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c
dolphi86 [110]

Given:

(ax+2)(bx+7)=15x^2+cx+14

And

a+b=8

Required:

To find the two possible values of c.

Explanation:

Consider

\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}

So

\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}

And also given

a+b=8---(2)

Now from (1) and (2), we get

\begin{gathered} a+\frac{15}{a}=8 \\  \\ a^2+15=8a \\  \\ a^2-8a+15=0 \end{gathered}a=3,5

Now put a in (1) we get

\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}

When a=5 and b=3, we have

\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}

Final Answer:

The option D is correct.

31 and 41

8 0
1 year ago
Answer...............
aev [14]

In the given graph point B is a relative maximum with the coordinates (0, 2).

The given function is y=x^{4}-2x^{2} +1.

In the given graph, we need to find which point is a relative maximum.

<h3>What are relative maxima?</h3>

The function's graph makes it simple to spot relative maxima. It is the pivotal point in the function's graph. Relative maxima are locations where the function's graph shifts from increasing to decreasing. A point called Relative Maximum is higher than the points to its left and to its right.

In the graph, the maximum point is (0, 2).

Therefore, in the given graph point B is a relative maximum with the coordinates (0, 2).

To learn more about the relative maximum visit:

brainly.com/question/2321623.

#SPJ1

8 0
2 years ago
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