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meriva
4 years ago
13

The Rockford's have a square play area that is built around a center sandbox that is in the shape of a circle. The sides of the

play area are tangent to the circle. They want to determine the amount of grass seed to buy for the spring. If the diameter of the circular sandbox is represented by d use function notation to write a function to represent the play area only.
Mathematics
1 answer:
stealth61 [152]4 years ago
5 0
<span>The area of the square is d^2. The area of the circle sandbox is πr^2=πd^2/4. So the area of play area only is equal to square area minus circle area which is d^2-πd^2/4.</span>
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$6,000 dollars is invested in two different accounts earning 3% and 5% interest. at the end of one year, the two accounts earned
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<u>Answer-</u>

<em>$2000</em><em> were invested at 5%</em>

<u>Solution-</u>

Let x amount of money was invested at 5% and (6000-x) amount was invested as 3%

We know that,

i=\dfrac{P\cdot r\cdot t}{100}

Putting the values,

i_1=\dfrac{P_1\cdot r_1\cdot t}{100}

i_1=\dfrac{x\cdot 5\cdot 1}{100}=\dfrac{5x}{100}

And

i_2=\dfrac{P_2\cdot r_2\cdot t}{100}

i_2=\dfrac{(6000-x)\cdot 3\cdot 1}{100}=\dfrac{3(6000-x)}{100}

According to the question,

\Rightarrow \dfrac{5x}{100}+\dfrac{3(6000-x)}{100}=220

\Rightarrow \dfrac{5x+3(6000-x)}{100}=220

\Rightarrow 5x+3(6000-x)=22000

\Rightarrow 5x+18000-3x=22000

\Rightarrow 5x-3x=22000-18000

\Rightarrow 2x=4000

\Rightarrow x=2000

Therefore, $2000 were invested at 5%

8 0
4 years ago
Read 2 more answers
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Answer:

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4 0
2 years ago
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Answer:

\frac{ {x}  + 9}{x - 4}

Step-by-step explanation:

\frac{ {x}^{2}  + 5x - 36}{ {x}^{2}  - 16}  \\  \\  = \frac{ {x}^{2}  + 9x  - 4x- 36}{ {x}^{2}  -  {(4)}^{2} } \\  \\  = \frac{ x({x}  + 9)  - 4(x + 9)}{ (x + 4)(x - 4) }  \\  \\  = \frac{ ({x}  + 9) \cancel{(x  - 4)}}{  \cancel{(x + 4)}(x - 4) } \\  \\  = \frac{ {x}  + 9}{x - 4}

7 0
3 years ago
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