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meriva
3 years ago
13

The Rockford's have a square play area that is built around a center sandbox that is in the shape of a circle. The sides of the

play area are tangent to the circle. They want to determine the amount of grass seed to buy for the spring. If the diameter of the circular sandbox is represented by d use function notation to write a function to represent the play area only.
Mathematics
1 answer:
stealth61 [152]3 years ago
5 0
<span>The area of the square is d^2. The area of the circle sandbox is πr^2=πd^2/4. So the area of play area only is equal to square area minus circle area which is d^2-πd^2/4.</span>
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Two angles are supplementary to each other. If the first angle measures 58 then which of the following could be the measure of t
34kurt

Answer: 122°

Step-by-step explanation:

When an angle is supplementary to each other , it means the angle measures to 180°.

Now since one of the two angles is 58°, therefore, the other angle will be

180° - 58°

= 122°

6 0
3 years ago
Given f(x) and g(x) = f(x) + k, look at the graph below and determine the value of k.
EastWind [94]

Answer:

Step-by-step explanation:

F(x) G(x)

7 0
3 years ago
Starting in the 1970s, medical technology allowed babies with very low birth weight (VLBW, less than 1500 grams, about 3.3 pound
cluponka [151]

Answer:

The test statistic value using the VLBW babies as group 1 is z=-2.76±0.01 and the P-value for the test (±0.0001) is 0.0030.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (VLBW group), of size n1=244 has a proportion of p1=0.77049.

p_1=X_1/n_1=188/244=0.77049

The sample 2 (control group), of size n2=247 has a proportion of p2=0.79757.

p_2=X_2/n_2=197/247=0.79757

The difference between proportions is (p1-p2)=-0.02708.

p_d=p_1-p_2=0.77049-0.79757=-0.02708

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{188+197}{244+247}=\dfrac{385}{491}=0.988

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.988*0.012}{244}+\dfrac{0.988*0.012}{247}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00005}=\sqrt{0.0001}=0.0098

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.02708-0}{0.0098}=\dfrac{-0.02708}{0.0098}=-2.76

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(t

As the P-value (0.0030) is smaller than the significance level (0.05), the effect issignificant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

3 0
3 years ago
Gail can use her 12% employee discount once a week. Last Sunday, she bought a $45 sweater at 1/3 off and used her discount on th
NNADVOKAT [17]

Statement 1 : Gail bought a $45 sweater at 1/3 off.

<u>Discount in Sweater Purchase:</u>

\frac{1}{3} \; of \; 45 = \frac{1}{3} \times 45 \; = \;\frac{45}{3} =\$15

Statement 2: Gail can use her 12% employee discount once a week and used her discount on the suit priced at $140.

Discount in Suit Purchase:

12\% \; of \; 140 =\frac{12}{100}  \times  140 = 0.12 \times 140 = \$16.8

Conclusion:

<u>Discount in Suit Purchase ($16.8) is greater than Discount in Sweater Purchase ($15)</u>

8 0
3 years ago
Read 2 more answers
Can someone please help me
Contact [7]

slope = (6 - 1)/(-2 - 1) = 5/-3 = -5/3

Equation

y - 6 = -5/3 (x + 2)

Hope it helps

6 0
3 years ago
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