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meriva
3 years ago
13

The Rockford's have a square play area that is built around a center sandbox that is in the shape of a circle. The sides of the

play area are tangent to the circle. They want to determine the amount of grass seed to buy for the spring. If the diameter of the circular sandbox is represented by d use function notation to write a function to represent the play area only.
Mathematics
1 answer:
stealth61 [152]3 years ago
5 0
<span>The area of the square is d^2. The area of the circle sandbox is πr^2=πd^2/4. So the area of play area only is equal to square area minus circle area which is d^2-πd^2/4.</span>
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From a deck of 52 cards, one card is drawn at random. Match the following subsets with their correct probabilities.
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1.3/13(if you mean jacks queens and kings)
2.1/52
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A _______ divides an angle into two congruent angles
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Angle bisector would be the answer
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3 years ago
Which quadratic function shows a y-intercept of 4 and a maximum value of 5
Elena L [17]

Answer:

The 4th graph

Step-by-step explanation:

To have a maximum value, your parabola would have to open downwards. So the first 2 are wrong. Since your y-intercept is positive 4, your graph would have to touch the y axis at 4. The 3rd graph is wrong since it touches the y-axis at a negative point. The correct answer would be the 4th answer choice.

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3 years ago
A dog and a cat are 200 meters apart when they see each other. The dog can run at a speed of 30 meter per second, while the cat
LenKa [72]

Answer:

They'll meet after 200 meters , if they simultaneously start running towards each other.

Step-by-step explanation:

Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.

Dog: Distance =Speed x time: x=30t

Cat: Distance = 200-x

=24t

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So they will meet after 3.7 seconds

To check:

Distance travelled by dog :x=30(3.7)

=111.11 meters

Distance travelled by cat: 24t=24(3.7)

=88.89 meters

Therefore since they are travelling towards each other and their distance apart is 200 meters, after 3.7 seconds they will meet because dog travelled 111.11 meters and cat travelled 88.89 meters and they covered already 200 meters as the sum of 111.11+ 88.89

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6 0
2 years ago
If x = 5 and 5 = y, then x = y
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5 0
3 years ago
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