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NNADVOKAT [17]
3 years ago
9

Can somebody please solve these!!!

Mathematics
1 answer:
kolbaska11 [484]3 years ago
8 0
If you plug in what variable they give you... you can plug it into a calculator to get a direct answer... for example for number 15 plug in -4 for m in the equation and plug in 5 for every p in the equation and 3 for every q in the equation then solve
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Jc bent 26.32 on 8 gallons of gas how much wood he spend for 20
dedylja [7]
1) divide 26.32 by 8 = 3.29
2) 3.29 x 20= 65.80
3) he would spend 65.80 on 20 gallons of gas
4 0
3 years ago
Mr. Tragrr has $500.00 to spend at a bicycle store. All the prices listed down below include tax.
fgiga [73]

To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.

Spent so far:

... 273.98 + 3×7.23 +42.36 = 338.03

Remaining available funds:

... 500.00 -338.03 = 161.97

The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.

Mr. Traeger can buy two (2) cycling outfits with the remaining money.

_____

The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.

8 0
3 years ago
Read 2 more answers
2yx3x+46 can some help me please
const2013 [10]
2y*3x+46
3x+46=2y
(3x+46)/2=y
3/2x+23=y
y=3/2x+23
4 0
3 years ago
Help me pleaseeee :/
BartSMP [9]
1.3+-2.4= -1.1 hope I helped :)
8 0
3 years ago
Read 2 more answers
A ball is thrown straight up from a height of 3 ft with a speed of 32 ft/s. Its height above the ground after x seconds is given
IceJOKER [234]

Answer:

19ft

Step-by-step explanation:

Given the height of a ball above the ground after x seconds given by the quadratic function y = -16x2 + 32x + 3, we can find the maximum height reached by the ball since we are not told what to look for.

The velocity of the ball is zero at maximum height and it is expressed as:

V(x) = dy/dx

V(x) = -32x+32

Since v(x) = 0

0 = -32x+32

32x = 32

x = 32/32

x = 1s

Get the height y

Recall that y = -16x² + 32x + 3.

Substitute x = 1

y = -16(1)²+32(1)+3

y = -16+32+3

y = -16+35

y = 19ft

Hence the maximum height reached by the ball is 19ft

7 0
3 years ago
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