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3 years ago

What does Express $4 as a percentage of 50$ mean?

Mathematics

1 answer:

Gwar [14]3 years ago

4 0

That kinda means to see how many times 4 goes into 50 and write that as a percentage. Hoped I helped

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Calculate the mean and median of each data set and determine what type of distribution it has data set 1 : 5 8 9 6 3 2 10 8 5 4

Degger [83]

Answer:

set 1: mean 5.72 repeated

median: 5

set 2: mean: 5.27 repeated

median: 6

Step-by-step explanation:

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3 years ago

what TRANSFORMATIONS take place to the parent graph f(x)= log(x) to achieve the graph g(x)=log(-2x-4)+5?

Leona [35]

The -4 will translate the graph of f(x) 4 units to the right.
Then the -2 before the x will stretch it vertically with factor 2, then reflect it in the y -axis.
Finally the + 5 will translate the graph 5 units vertically upwards

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3 years ago

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4 years ago

Mr. Good Wrench advertises that a customer will have to wait no more than 30 minutes for an oil change. A sample of 26 oil chang

Andru [333]

Answer:

The 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

Step-by-step explanation:

The (1 - α)% confidence interval for the population standard deviation is:

$CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}$

The information provided is:

n = 26

s = 4.8 minutes

Confidence level = 90%

Compute the critical values of Chi-square as follows:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.10/2, (26-1)}=\chi^{2}_{0.05, 25}=37.652$

$\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.10/2, (26-1)}=\chi^{2}_{0.95, 25}=14.611$

*Use a Chi-square table.

Compute the 90% confidence interval for the population standard deviation waiting time for an oil change as follows:

$CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}$

$=\sqrt{\frac{(26-1)\times 4.8^{2}}{37.652}}\leq \sigma\leq \sqrt{\frac{(26-1)\times 4.8^{2}}{14.611}}\\\\=3.9113\leq \sigma\leq 6.2787\\\\\approx 3.9 \leq \sigma\leq6.3$

Thus, the 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

3 0

3 years ago

Can someone help me solve this problem?

ioda

The scale factor was D. 4. We can figure this out by multiplying 3 by 4 to get 12 and 1 by 4 which is 4 to get the dimensions of the larger triangle.
I hope this helped! :-)

6 0

4 years ago