Answer:
x = 8 units.
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
<em>The areas of the squares adjacent to two sides of a right triangle are 32 unit square and 32 units square. Find the length,x, of the third side of the triangle</em>
My answer:
- Let a is the side length of the 1st square
The area of the 1st square is equal to 32 units square
<=>
<=> a =
units
- Let b is the length of the 2nd square
The area of the 2nd square is equal to 32 units square
<=>
= 32
<=> b =
units
Applying the Pythagoras Theorem, we have:
<=>
<=> 
<=> x = 8 units
Hope it will find you well.
A(2,6) translation <span>A=(4,-5)
4 - 2 = 2
-5 - 6 = -11
rule
(x) --->(x + 2) (shifted 2 units to the right)
(y) --->(y - 11) (shifted 11 units down)
</span>
Answer:
6-2=4
31/5 x 8 = 248/40
15/8 x 5 = 75/40
248-75=173
4 13/40
answers in order
6-2=4
6 1/5 - 1 7/8 = 4 13/40
Hope this helps
Step-by-step explanation:
Factor the numbers, starting from the smallest:
792=2*3*3*11*4
990=2*3*3*11*5
the greatest whole number that can be divided by both 792 and 990 is 2*3*3*11=198
the smallest whole number that can divide both 792 and 990 exactly is 2*3*3*11*4*5=3960
Not sure which one you are asked to find.
Answer:
2&6and3&7
Step-by-step explanation:
I am sure of it