Interest earned $837

Suppose that y varies directly with x and at the same time varies inversely with z and y=12 when x=6 and z=-2. Write the equatio

ki77a [65]

Answer:

Answer:

y =18

Explanation

Step-by-step explanation:

3 0

2 years ago

I am a graph that uses pictures to show and compare information

andrew-mc [135]

Answer:

thats cool

Step-by-step explanation:

explain why you are a graph that uses pictures to show and compare information.

7 0

3 years ago

Find y' by implicit differentiation √x +√y =1

AleksandrR [38]

Differentiate both sides with respect to x

$\frac{d}{dx}(x^{\frac{1}{2}} + y^{\frac{1}{2}}) = \frac{d}{dx}(1)\\\\ \frac{1}{2x^{\frac{1}{2}}} + \frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = 0\\\\\frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = -\frac{1}{2x^{\frac{1}{2}}}\\\\\frac{1}{2\sqrt{y}}\frac{dy}{dx} = -\frac{1}{2\sqrt{x}} \\\\\frac{dy}{dx} = -\frac{1}{2\sqrt{x}} \times 2\sqrt{y}\\\\\frac{dy}{dx} = -\frac{\sqrt{y}}{\sqrt{x}} \\\\\boxed{\bf{y'= -\frac{\sqrt{y}}{\sqrt{x}}}}$

5 0

2 years ago

Can yall help me out

Nastasia [14]

Answer:

Question 1 (1 point)

1. An object has a mass of 25g and a volume of 5ml

a

10

b

8

c

5

d

7

Question 2 (1 point)

2. An object has a mass of 30g and a volume of15ml. What is the density?

a

10

b

2

c

3

d

5

Question 3 (1 point)

3. An object has a mass of 200g and a volume of 100ml. What is the density?

a

2

b

4

c

6

d

8

Question 4 (1 point)

4. An object has a mass of 17g and a volume of 2ml. What is the density?

a

2.4

b

2

c

8

d

8.5

Question 5 (1 point)

5. An object has a mass of 20g and a volume of 5ml. What is the density?

a

2

b

4

c

10

d

2.5

Question 6 (1 point)

6. An object has a mass of 75g and a volume of 75ml. What is the density?

a

6

b

1

c

7

d

8

Question 7 (1 point)

7. An object has a volume of 100ml and a mass of 2oo ml. What is the density?

a

0.5

b

1

c

4

d

2.5

Question 8 (1 point)

8. An object has a volume of 5ml and a mass of 650 g. What is the density?

a

110

b

120

c

130

d

200

Question 9 (1 point)

9. An object has a mass of 15g and a volume of 5ml. What is the density?

a

2.5

b

7

c

3

d

2.56

Question 10 (1 point)

10. An object has a mass of 13g and a volume of 2ml. What is the density?

a

6.5

b

3.7

c

4

d

Step-by-step explanation:

7 0

2 years ago

In a recent year, a poll asked 2362 random adult citizens of a large country how they rated economic conditions. In the poll,

Harman [31]

Answer:

a) The 99% confidence interval is given by (0.198;0.242).

b) Based on the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

c) $\alpha=0.01$

Step-by-step explanation:

Data given and notation

n=2362 represent the random sample taken

X represent the people who says that they would watch one of the television shows.

$\hat p=\frac{X}{n}=0.22$ estimated proportion of people rated as Excellent/Good economic conditions.

$p_o=0.24$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that 24% of people are rated with good economic conditions:

Null hypothesis: $p=0.24$

Alternative hypothesis: $p \neq 0.24$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Part a: Test the hypothesis

Check for the assumptions that he sample must satisfy in order to apply the test

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

np = 2362x0.22=519.64>10 and n(1-p)=2364*(1-0.22)=1843.92>10

Condition satisfied.

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.22 -0.24}{\sqrt{\frac{0.24(1-0.24)}{2362}}}=-2.28$

The confidence interval would be given by:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The critical value using $\alpha=0.01$ and $\alpha/2 =0.005$ would be $z_{\alpha/2}=2.58$ . Replacing the values given we have:

$0.22 - (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.198$

$0.22 + (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.242$

So the 99% confidence interval is given by (0.198;0.242).

Part b

Statistical decision 

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided is $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So based on the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

Part c

The confidence level assumed was 99%, so then the signficance is given by $\alpha=1-confidence=1-0.99=0.01$

6 0

2 years ago