The result of the square root of the equation A = 121 ft² is √A = 11 ft
<h3>What are square roots?</h3>
Square roots are numbers multiplied by itself to give another number
<h3>How to determine the square root?</h3>
The equation is given as:
A = 121 ft²
Take the square root of both sides
√A = √121 ft²
Evaluate the square root
√A = 11 ft
Hence, the square root of the equation A = 121 ft² is √A = 11 ft
Read more about square roots at:
brainly.com/question/98314
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Answer:
97.98
Step-by-step explanation:
The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;
Area of the parallelogram = |PQ×PS|
PQ = Q-P and PS = S-P
Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)
PQ = (4,-5,3) - (0,0,0)
PQ = (4,-5,3)
Also, PS = S-P
PS = (8,-12,4)-(0,0,0)
PS = (8,-12,4)
Taking the cross product of both vectors i.e PQ×PS
(4,5,-3)×(8,-12,4)
PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k
PQ×PS = -16i - 40j -88k
|PQ×PS| = √(-16)²+(-40)²+(-88)²
|PQ×PS| = √256+1600+7744
|PQ×PS| = √9600
|PQ×PS| ≈ 97.98
Hence the area of the parallelogram is 97.98
Find the factors of -3:
1,-3 and 3,-1
which ever adds up to 1 multiplied by 2
the answer is (2x+3)(x-1)
hope this helps
Answer:
20
Step-by-step explanation:
Two tangent segments drawn to a circle from the same point outside the circle are congruent. The two tangents at A measure 2. The two tangents at B measure 5. The two tangents at C measure 3.
perimeter = 2 + 2 + 5 + 5 + 3 + 3
perimeter = 20
5500+100.50x=4597+<span>175.75x
</span>175.75x-100.50x=5500-4597
75.25x= 903
x=903/75.25
x=12
for 12 ton of sugar <span>the two companies charge the same</span>
