(f o g o h)(x) = f { g [ h(x) ] }
Which means: apply first function h, then apply function g to the result, and finally apply function f to the new result.
h(25) = √25 = 5
g(5) = 5 - 3 = 2
f(2) = 3(2) = 6.
Answer: 6
Answer:
At (-2,0) gradient is -4 ; At (2,0) gradient is 4
Step-by-step explanation:
For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).
y = x^2 - 4
y' = 2x
The function y = x^2 - 4 cross the x-axis when:
y = x^2 - 4
0 = x^2 - 4
4 = x^2
2 +/- = x
Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).
The gradient at these points are as follows:
y' = 2(-2) = -4
y' = 2(2) = 4
Cheers.
6 + 9y - 18 = -3 Combine like terms (6 and -18)
9y - 12 = -3 Add 12 to both sides
9y = 9 Divide both sides by 9
y = 1
