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3 years ago

Chapter 8 question 18 please help

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

4 0

4744 feet. work below. please mark brainliest.

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Find the equation of a line that passes through (2,8) and is parallel to the graph of y=2x+6. Write the equation in slope-interc

Rashid [163]

Answer:

The equation of a parallel line would be y = 2x + 4

Step-by-step explanation:

In order to find the equation of this line, we first have to note that paralell lines have same slopes. Therefore, since the original line has a slope of 2, we know the new line will have a slope of 2. Now we can use that information along with the given point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 8 = 2(x - 2)

y - 8 = 2x - 4

y = 2x + 4

3 0

3 years ago

13. Pete traveled 1,380 miles in two days. The first day, he traveled 1.5 times as far as he did the second day. How many miles

ArbitrLikvidat [17]

i think it would be a. 920

5 0

3 years ago

Read 2 more answers

Sec squared 55 - tan squared 55

sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55 = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

$\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}$

And,

$\tan \theta=\frac{\text { perpendicular }}{\text { base }}$

where Ө is the angle

Substituting the values

$\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}$

Solving,

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}$

According to Pythagoras theorem,

$\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}$

Putting this in the equation;

squared 55 - tan squared 55 =

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1$

Therefore, sec squared 55 – tan squared 55 = 1

6 0

3 years ago

The point (3,9) lies in which quadrant?

borishaifa [10]

Answer:

Wheres the actual graph with the quadrants?

6 0

3 years ago

Read 2 more answers

The inverse of F(x) is a function

Sladkaya [172]

Step-by-step explanation:

Let f be a function having domain in the set X, and range in the set Y. Then f would be invertible if there exists a function g having domain Y and range X, such as:

${\displaystyle f(x)=y\,\,\Leftrightarrow \,\,g(y)=x$

In other words, the function $f$ is applied to an input x, and gives an outcome of y, then its inverse function, let say $g$ , can be applied to y to give the result of x.

In other words,

y = f(x) if and only if x = g(y)

For example, considering the function

$\:\:f\left(x\right)=b\:-x$

the inverse is:

$f^{-1}\left(y\right)=b\:-y$

4 0

3 years ago