1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stealth61 [152]
3 years ago
8

Chapter 8 question 18 please help

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0
4744 feet. work below. please mark brainliest.
You might be interested in
Find the equation of a line that passes through (2,8) and is parallel to the graph of y=2x+6. Write the equation in slope-interc
Rashid [163]

Answer:

The equation of a parallel line would be y = 2x + 4

Step-by-step explanation:

In order to find the equation of this line, we first have to note that paralell lines have same slopes. Therefore, since the original line has a slope of 2, we know the new line will have a slope of 2. Now we can use that information along with the given point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 8 = 2(x - 2)

y - 8 = 2x - 4

y = 2x + 4

3 0
3 years ago
13. Pete traveled 1,380 miles in two days. The first day, he traveled 1.5 times as far as he did the second day. How many miles
ArbitrLikvidat [17]
 i think it would be a. 920
5 0
3 years ago
Read 2 more answers
Sec squared 55 - tan squared 55
sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55  = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}

And,

\tan \theta=\frac{\text { perpendicular }}{\text { base }}

where Ө is the angle

Substituting the values

\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}

Solving,

\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}

According to Pythagoras theorem,

\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}

Putting this in the equation;

squared 55 - tan squared 55 =

\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1

Therefore, sec squared 55 – tan squared 55 = 1

6 0
3 years ago
The point (3,9) lies in which quadrant?
borishaifa [10]

Answer:

Wheres the actual graph with the quadrants?

6 0
3 years ago
Read 2 more answers
The inverse of F(x) is a function
Sladkaya [172]

Step-by-step explanation:

Let f be a function having domain in the set X, and range in the set Y. Then f would be invertible if there exists a function g having domain Y and range X, such as:

{\displaystyle f(x)=y\,\,\Leftrightarrow \,\,g(y)=x

In other words, the function f is applied to an input x, and gives an outcome of y, then its inverse function, let say g, can be applied to y to give the result of x.

In other words,

y = f(x) if and only if x = g(y)

For example, considering the function

\:\:f\left(x\right)=b\:-x

the inverse is:

f^{-1}\left(y\right)=b\:-y

4 0
3 years ago
Other questions:
  • If AB= 2x+1 and BC=5x-14 Find AC
    5·1 answer
  • Doug entered a canoe race he rowed 3 1/2 miles in 1/2 hour what is his average speed in miles per hour
    14·1 answer
  • Write out the form of the partial fraction decomposition of the function (as in this example). Do not determine the numerical va
    13·1 answer
  • \324 plzzzzzzzzzz help
    15·1 answer
  • Helppppp me please !!!!
    13·1 answer
  • Mindy has $10.75 to buy school supplies. She spends $3.96 at one store for a package of glue sticks, but she still needs to buy
    12·2 answers
  • Help me figure out what x is
    6·1 answer
  • Examine the diagram. Parallel lines a and b are crossed by transversal t to create 8 angles. Clockwise from top left, the angles
    13·2 answers
  • Question 5 of 10
    6·1 answer
  • What is the base of a triangle with an area of 207 square inches and a height of 18 inches
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!