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gavmur [86]
3 years ago
12

Write a equation of the line whose slope is -1/2 and whose y-intercept is 4

Mathematics
2 answers:
Shtirlitz [24]3 years ago
4 0

Answer:

Hi there!

An equation for this is:

-1/2x +4

Step-by-step explanation:

The <u>slope</u> is always in front of the "x"! The y intercept is always added to the slope!

Hope this helps

tigry1 [53]3 years ago
4 0

Answer:

y = -1/2x +4

Step-by-step explanation:

The slope intercept form of a line is given by

y = mx+b  where m is the slope and b is the y intercept

y = -1/2x +4

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Parallelogram ABCD is translated (x + 3, y − 2) and then rotated 90° about the origin in the clockwise direction. Complete the t
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Answer: A″ (−1, 2), B″ (1, 1), C″ (1, −1), D″ (−1, −2)

Step-by-step explanation:

  • there are basically 2 parts in the question.
  • first one is the translation(easier one)

after translation, the corresponding points will be:

A (− 5, 1)   --> a(-5+3,1-2) = (-2,-1)

B (−4, 3)  --> b(-4+3,3-2) = (-1,1)

C (−2, 3)  --> c(-2+3,3-2) = (1,1)

D (−1, 1)    --> d(-1+3,1-2)  = (2,-1)

  • now the second part:

let (x,y) be a point and if it is rotated by "\alpha"

then, the new coordinates (x',y') will be :

x'= xcos\alpha +ysin\alpha

y'=-xsin\alpha +ycos\alpha

here, \alpha = 90 degrees

so,

a(-2,-1)  --> A"(-2cos[90]-1sin[90], -[-2]sin[90]+[-1]cos[90]) =(0-1, 2+0)=(-1,2)

(since, cos[90]=0, sin[90]=1)

b(-1,1)    -->B"(-1cos[90]+1sin[90], -[-1]sin[90]+1cos[90])=(1,1)

c(1,1)     --> C"(1cos[90]+1sin[90],-[1]sin[90]+1cos[90]) = (1,-1)

d(2,-1)   --> D"(2cos[90]+[-1]sin[90],-2sin[90]+[-1]cos[90]) =(-1,-2)

these are the coordinates after both the transformations.

7 0
4 years ago
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Q is directly proportional to r. q is 76 when r is 20. work out q when r is 45.
pashok25 [27]
Q α r
q=kr
thus
k=q/r
when r=20, q=76
hence
k=76/20=
q=76/20r
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q=171
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I need help asap please help me
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Answer:

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Step-by-step explanation:

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