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ASHA 777 [7]
3 years ago
9

I need help asap please help me

Mathematics
1 answer:
slava [35]3 years ago
3 0

Answer:

28/41

Step-by-step explanation:

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Can you explain with work please
kari74 [83]
So what is happening is you need to find out the unknown length. Because the side EH is similar to side AD ( its similar because the shape has been rotated) you can put them over one another. Now you need to have another equal side to complete the problem so you use the other set  of sides.  To make this problem easier we should make the side EH into a variable. to make it AD over X. now the problem is BC over FG is = to AD over X. The next step is to simplify into numbers because it is hard to just work with letters. So now the problem is 12 over 30 = 16 over X. The next step is to cross multiply so the problem is 12X = 30 x 16. Now we can simplify this equation to 12X= 480. the next thing you want to do is to divide 240/12 because you need to get X by its self. Resulting in (Remember X stands for EH)  EH = 40in.                                                  
5 0
3 years ago
Please help me with this I don’t get it at all
dalvyx [7]
Since this is half a square you would find the volume and then divide by 2 and you will get 280 cubic inches.
3 0
3 years ago
A car drives 195 miles in 3 hours and 15 mins.<br> what is the average speed of the car?
maria [59]

Answer:

one mile per hour

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The domain for f(x) and g(x) is the set of all real numbers.
zvonat [6]

Answer:

it's the first choice: 2x^3 +  5x^2 - x - 6.

Step-by-step explanation:

(f•g)(x)

= f(x) * g(x)

= (x + 2)(2x^2 + x - 3)

= 2x^3  + x^2 - 3x + 4x^2 + 2x - 6

= 2x^3 +  5x^2 - x - 6.

7 0
4 years ago
Let the geometric sequence {an} be defined as follows: {12, 6, 3, 3 /2 , 3 /4 , 3/ 8 ,...} Find the sum of the entire sequence,
Korolek [52]

Answer:

A) 24

Step-by-step explanation:

The given geometric series is {12, 6, 3, 3 /2 , 3 /4 , 3/ 8 ,...}

Each term can be represented as a product of its previous term and \[\frac{1}{2}\]

The generic term of the series can be represented as the product of the first term 12 and \[\frac{1}{2}^{n-1}\] where n is the index of the term in the series.

The sum to infinity of such a series is given by the following formula:

\[\frac{term1}{1-ratio}\]

Substituting and calculating:

\[\frac{12}{1-\frac{1}{2}}\]

=\[\frac{12}{\frac{1}{2}}\]

=12*2 = 24

8 0
4 years ago
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