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3 years ago

If a rectangle has a width of

Mathematics

1 answer:

Elanso [62]3 years ago

3 0

Answer:

The rectangle doesn't exists

Step-by-step explanation:

(4x+3).(x+1)= ?

4x² + 4x + 3x + 3 = ?

4x² + 7x + 3 = ?

4 = a

7 = b

3 = c

delta = b² - 4.a.c

delta = 7² - 4.4.3

delta = 49 - 4.4.3

delta = 49 - 48

delta = 1

x1 = -b + (square root)delta / 2.a

x1 = -7 + 1/2.4

x1 = -6 / 8

x2 = -7 - 1/2.4

x2 = -8/8

x2 = -1

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A number increased by 5 and divided by 2 is equal to 75. What is the number?

USPshnik [31]

Answer:

145

Step-by-step explanation:

We will let x equal our unknown number. So:

(x + 5)/2 = 75

Now we can solve for x

We can first multiply both sides of the equation by 2. This will get rid of the fraction on the left side:

x + 5 = 75 * 2 ----->

x + 5 = 150

Next, subtract 5 from both sides:

x + 5 - 5 = 150 - 5 ----->

x = 145

7 0

3 years ago

An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

$-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0$

Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$