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3 years ago

7

Which shows 23^2017^2 being evaluated using the difference of perfect squares method?

1 answer:

Alla [95]3 years ago

8 0

Im not sure i think its D...?

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5 tens + 5 tens in standard form

Alexeev081 [22]

5 ten is equal to 50.
So, then what is 50 + 50
100

7 0

3 years ago

Read 2 more answers

Find the volume of the cylinder in terms of x?

Butoxors [25]

V=127.16pi m^3

The formula for the Volume of a Cylinder is V=(pi)r^2h

First we have to fill in the variables with the information we have. The radius is 3.4m. The height is 11m. We want to leave the answer in terms of pi, so we won't multiply by pi at all. Let's plug it in.
V=(pi)3.4^2•11

To square a number we multiply it by itself, so 3.4 • 3.4 equals 11.56.
V=(pi)11.56•11

Next, we multiply the radius squared, which we already found by the height of the cylinder which is 11. 11.56 times 11 equals 127.16.

V=127.16pi
We found the final answer and don't use pi since we want it in terms of pi. Since a Cylinder is a 3-D figure, that means the units of measurement is cubed.

The answer is A) 127.16pi m^3

4 0

3 years ago

Of all customers purchasing automatic garage-door openers, 75% purchase Swedish model. Let X = the number among the next 15 purc

Lelechka [254]

Answer:

a)

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

b)

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = 0.2737

d) μ = 15*0.75 = 11.25. σ² = 11.25*0.25 = 2.8125

Step-by-step explanation:

X is a binomial random variable with parameters n = 15, p = 0.75. Therefore

a)

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

b)

P(X>10) = P(X=11) + P(X=12)+ P(X=13)+P(X=14)+P(x=15)

$P(X=11) = {15 \choose 11} * 0.75^{11} * 0.25^4 = 0.2252$

$P(X=12) = {15 \choose 12} * 0.75^{12} * 0.25^3 = 0.2252$

$P(X=13) = {15 \choose 13} * 0.75^{13} * 0.25^2 = 0.1559$

$P(X=14) = {15 \choose 14} * 0.75^{14} * 0.25 = 0.0668$

$P(X=15) = {15 \choose 15} * 0.75^{15} = 0.0134$

Thus,

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = P(X = 6) + P(X = 7) + P(X = 8) + P(X=9) + P(X=10)

$P(X=6) = {15 \choose 6} * 0.75^{6} * 0.25^9 = 0.0034$

$P(X=7) = {15 \choose 7} * 0.75^{7} * 0.25^8 = 0.0131$

$P(X=8) = {15 \choose 8} * 0.75^{8} * 0.25^7 = 0.0393$

$P(X=9) = {15 \choose 9} * 0.75^{9} * 0.25^6 = 0.0918$

$P(X=10) = {15 \choose 10} * 0.75^{10} * 0.25^{5} = 0.1652$

Thereofre,

$P(6 \leq X \leq 10) = 0.0034 + 0.0134 + 0.0393 + 0.0918 + 0.1652 = 0.2737$

d) μ = n*p = 15*0.75 = 11.25

σ² = np(1-p) = 11.25*0.25 = 2.8125

3 0

3 years ago

what rate of interest is required to reach an accumulated future value of $100 if a principal of $50 is invested for 10 years an

Nookie1986 [14]

100*10=1000

50*10=500

1000-500= 500

5 0

3 years ago

A function has cheating x's.<br> True<br> False

Assoli18 [71]

True
Hope this helps
Have a wonderful day or night

8 0

3 years ago