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KatRina [158]
3 years ago
12

Betty is allergic to milk products. She discovers that 40% of the food items available in the school cafeteria contain milk prod

ucts. She wants to know the odds of the cafeteria serving three meals in a row containing milk products so she can decide whether she should bring lunch from home. How can she simulate this situation to find the relative frequency?
Mathematics
1 answer:
viktelen [127]3 years ago
4 0

Answer:

The ratio of food items containing milk products to those without milk is 40:60 or 2:3. So Betty's simulation should have a multiple of 5 possible outcomes. She can model this situation using a 5-section spinner with 2 sections representing items containing milk and three sections representing items without milk. To find the odds of the cafeteria serving 3 meals in a row containing milk, spin the spinner 3 times. If all 3 spins land on sections representing food items that contain milk, it would mean the cafeteria would serve 3 meals in a row containing milk. To find the relative frequency of the event, Betty needs to perform the simulation multiple times.

Step-by-step explanation:

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Because the 0.96 is less than 1, it means that the house loses value over the years.

Convert 0.96 to a percent: 0.96 = 96%

100% - 96% = 4%

The house loses 4% of it's value every year.

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3 years ago
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4 years ago
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Eliza falls asleep at 9:35 pm and wakes up 8 hours and 45 miunets later, what time does she wake uo
alexdok [17]

Answer: Eliza wakes up at 6:25 A.M.

Step-by-step explanation:

What I did is first used the 45 minutes to make the time 10:00 P.M. which leaves you with 8 hours and 25 minutes, then i added the 8 hours onto 10:00 P.M. which leaves you at 6:00 A.M. with 25 minutes left, then you add the 25 minutes onto 6:00 A.M. which puts it at 6:25 A.M.

6 0
3 years ago
HELP++++++++++++++++++++++++
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Answer:

ASA

ΔFGH ≅ ΔIHG ⇒ answer B

Step-by-step explanation:

* Lets revise the cases of congruence  

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and  

 including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ  

 ≅ 2 angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles  

 and one side in the 2ndΔ  

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

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* Lets prove the two triangles FGH and IHG are congruent by on of

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∵ FG // HI and GH is transversal

∴ m∠FGH = m∠IHG ⇒ alternate angles

- In the two triangles FGH and IHG

∵ m∠FHG = m∠IGH ⇒ given

∵ m∠FGH = m∠IHG ⇒ proved

∵ GH = HG ⇒ common side

∴ ΔFGH ≅ ΔIHG ⇒ ASA

* ASA

 ΔFGH ≅ ΔIHG

3 0
3 years ago
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QveST [7]

Answer:

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8 0
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