The cross product of the normal vectors of two planes result in a vector parallel to the line of intersection of the two planes.
Corresponding normal vectors of the planes are
<5,-1,-6> and <1,1,1>
We calculate the cross product as a determinant of (i,j,k) and the normal products
i j k
5 -1 -6
1 1 1
=(-1*1-(-6)*1)i -(5*1-(-6)1)j+(5*1-(-1*1))k
=5i-11j+6k
=<5,-11,6>
Check orthogonality with normal vectors using scalar products
(should equal zero if orthogonal)
<5,-11,6>.<5,-1,-6>=25+11-36=0
<5,-11,6>.<1,1,1>=5-11+6=0
Therefore <5,-11,6> is a vector parallel to the line of intersection of the two given planes.
I seef(x) between 0 to 1 is goes to xfinity but in the negative direction
We can say it is large neagtive numbet when x is between 0 and 1
I think it would be y=1x+(0-2)
Answer: 23in squared
Step-by-step explanation:
9 plus 4 plus 10
Answer:
your answer is correct
Step-by-step explanation:
-5 x -4=20
20+3=23
