<img src="https://tex.z-dn.net/?f=4x%20-%2010%20%3D2" id="TexFormula1" title="4x - 10 =2" alt="4x

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Elena-2011 [213]

2 years ago

ss="latex-formula">4x - 10 = 2

Mathematics

2 answers:

Citrus2011 [14]2 years ago

6 0

If I’m correct it should be X=3

andrezito [222]2 years ago

3 0

Answer:

Explanation:

4x - 10 = 2

<u>Add 10 To Both Sides</u>

4x - 10 + 10 = 2 + 10

4x = 12

<u>Divide Both Sides By 4</u>

4x / 4 = 12 / 4

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Hello, please consider the following.

When $x_1$ and $x_2$ are two roots, we can factorise as

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and the product is

$\dfrac{a^2b^2}{4}=\dfrac{a^2}{2}\dfrac{b^2}{2}$

So we can factorise as below.

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And the solutions are

$\boxed{\sf \n\bf \ \dfrac{a^2}{2} \ \ and \ \ \dfrac{b^2}{2}}$

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Let's do it!

$9x^2-9(a+b)x+2a^2+5ab+2b^2=0\\\\9(x-\dfrac{a+b}{2})^2-9\dfrac{(a+b)^2}{4}+2a^2+5ab+2b^2=0\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{9(a+b)^2-8a^2-20ab-8b^2}{4}\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{9a^2+18ab+9b^2-8a^2-20ab-8b^2}{4}\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{a^2+b^2-2ab}{4}=\dfrac{(a-b)^2}{4}\\\\(x-\dfrac{a+b}{2})^2=\dfrac{(a-b)^2}{2^2\cdot 3^2}$