Answer: 257
Step-by-step explanation:
Using the formula of test statistic, the value of the test statistic is 2.6961.
The mean of the public accountant is
Mean x(p) =50.2+59.8+57.3+59.2+53.2+56.0+49.9+58.5+56.0+51.9/10
x(p) = 55.2
Now the standard deviation of public accountant is
SD(p) = √{∑(x-x(p))^2/n-1}
SD(p) = √(50.2-55.2)^2+(59.8-55.2)^2+..................+(51.9-55.2)^2/n-1
After solving;
SD(p) = 3.34
The mean of the financial planner is
Mean x(F) =48.0+49.2+53.1+55.9+51.9+53.6+49.7+53.9+52.8+48.9/10
x(F) = 51.6
Now the standard deviation of financial planner is
SD(F) = √{∑(x-x(p))^2/n-1}
SD(F) = √(48.0-51.6)^2+(49.2-51.6)^2+..................+(48.9-51.6)^2/n-1
After solving;
SD(F) = 2.57
Test Statistic (t) =
t =
After solving
t = 2.6961
Hence, the value of the test statistic is 2.6961.
To learn more about test statistic link is here
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The right question is
public accountant 50.2 59.8 57.3 59.2 53.2 56.0 49.9 58.5 56.0 51.9
financial planner 48.0 49.2 53.1 55.9 51.9 53.6 49.7 53.9 52.8 48.9
Use a 0.05 level of significance and test the hypothesis that there is no difference between the starting annual salaries of public accountants and financial planner
Find the value of the test statistic.
Answer:
-4
Step-by-step explanation:
There are many methods to solve this system of equations.
I will use the elimination method.
First step:
Multiply the first equation by -2
2(2x-3y) = -14(-2)
-4x + 6y = 28
Multiply the second equation by 3 so you can eliminate the y term
3(3x-2y) = -6(3)
9x-6y = -18
Second step: Add the equations vertically(Basically adding like terms)
-4x+6y = 28
+
9x - 6y = -18
5x = 10
Third step: Solve for x
x = 2
Substitute the x-value into any of the original equation to get the y value
3(x) - 2y = -6
3(2) - 2y = -6
6 - 2y = -6 (Since we are solving for y, it will be isolated and we will move 6 to the other side)
-2y = -6 - 6(Moving 6 to the other side makes it negative)
Solve for y by dividing by -2
y = 6
So (x, y) = (2, 6)
Since the question is asking to subtract x and y
2-6 = -4
1) Since x = -4 and x = -6 are zeros, then, by definition, (x + 4) and (x + 6) are factors of the polynomial. Another way in understanding this is that when x = -4, there would be no remainders.
Thus, we can simply write it as: P(x) = (x + 4)(x + 6) = x² + 10x + 24 (ie C)
2) Using the discriminant, we can find whether a quadratic has two, one, or no roots at all. Symbolised as delta (Δ), the discriminant formula goes as follows:
Δ = b² - 4ac
Thus, if we move the 3 to the other side, we get:
Δ = (-5)² - 4(3)(-10) > 0
Since Δ > 0, then there lies two solutions.
To find rationality or irrationality, we need to check whether or not the square root of the discriminant is an integer or not. If the square root of the discriminant is not an integer, we have irrational roots.
Thus, we've worked out that the discriminant is 145. But 145 is not a perfect square, so when we take the square root of it, we get irrational roots.
Hence, we have two irrational roots.
3) Since we have a fraction, we know that the denominator cannot be zero. Thus, to find places where undefined x-values occur, we need to let the denominator equal to zero:
x² - 16 = 0
x² = 16
x = 4 and -4
These are the restricted values for x, since x cannot equal to 4, or -4.
Hence, your answer is x = 4, -4
4) We can expand and move everything to the LHS.
2(x + 2)² - 32 = 0
2(x² + 4x + 4) - 32 = 0
2x² + 8x + 8 - 32 = 0
2x² + 8x - 24 = 0
We can factorise 2 outside.
2(x² + 4x - 12) = 0
x² + 4x - 12 = 0
We can factorise this further.
(x + 6)(x - 2) = 0
x = -6, 2 are our solutions.
This problem can be looked at like a right triangle, where the hypotenuse is 750 and one leg is 450. Thus 450^2 + the length of the park^2 = 750 ^2.
202500 + the length of the park^2 = 562500
the length of the park^2 = 360000
the length of the park = 600
Hope it helps <3