Ask question

Ask question

All categories

3 years ago

13

What is the sample space for the probability model?

2 answers:

Sonja [21]3 years ago

7 0

Answer:

sample space for a probability model is the set of all possible outcomes

muminat3 years ago

3 0

Sample space for the probability model is the set of all possible outcomes. ❤️

You might be interested in

Please help this is due today!!!<br><br>

Nikolay [14]

Answer:

3. 9 - (n ÷ 5 ) 5. 8 x ( 5 x t ) (( i don't know the others ))

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Kevin is taking a taxi from the airport to his home. There is a $6 fee for riding in the taxi. In

Oxana [17]

6+1m= t. That’s the equation for the problem.

7 0

2 years ago

Read 2 more answers

Can you help me with my math questions

GrogVix [38]

$p^2+2(7)p+7^2=(p+7)^2$

Justification:

Given: $p^2+14p+49$

Split the middle term;

$=p^2+7p+7p+49$

Factor:

$=p(p+7)+7(p+7)$

$=(p+7)(p+7)$

$=(p+7)^2$

QUESTION 3a

The given expression for the area of the rectangle is $36x^2-12x+1$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$36x^2-12x+1=289$

$\Rightarrow (6x-1)^2=289$

$\Rightarrow (6x-1)(6x-1)=289$

$\Rightarrow l=(6x-1),w=(6x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow (6x-1)=\pm \sqrt{289}$

$\Rightarrow (6x-1)=\pm 17$

$\Rightarrow 6x=1\pm 17$

$\Rightarrow 6x=18 \:or\:6x=-16$

$\Rightarrow x=3 \:or\:x=-\frac{2}{3}$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=(6(3)-1)=17,w=6(3)-1=17$

QUESTION 3b

The given expression for the area of the rectangle is $25x^2-50x+25$ .

This is equal to the indicated area which is $1225\;in^2$

This implies that

$25x^2-50x+25=1225$

$25(x^2-2x+1)=1225$

$(5(x-1))^2=35^2$

$5(x-1)5(x-1)=49$

$\Rightarrow l=5(x-1),w=5(x-1)$

This implies that, the dimensions of the rectangle are equal;

Using the square root method, we obtain

$\Rightarrow 5(x-1)=\pm \sqrt{1225}$

$\Rightarrow 5(x-1)=\pm 35$

$\Rightarrow x=1\pm 7$

$\Rightarrow x=8 \:or\:x=-6$

We discard the negative value.

The side length of this rectangle is

$\Rightarrow l=5(8-1)=35,w=5(8-1)=35$

QUESTION 3c

The given expression for the area of the rectangle is $49x^2-56x+16$ .

This is equal to the indicated area which is $289\;in^2$

This implies that

$49x^2-56x+16=289$

$(7x-4)^2=289$

$(7x-4)(7x-4)=289$

$\Rightarrow l=(7x-4),w=(7x-4)$

Applying the laws of indices gives;

$(7x-4)^2=17^2$

This implies that;

$7x-4=17$

$7x=21$

$x=3in.$

The side length of this rectangle is

$\Rightarrow l=7(3)-4=17\:in.,w=7(3)-4=17\:in.$

Dont forget that the square is also a rectangle.

5 0

3 years ago

Read 2 more answers

Help !!!<br>See question in image.<br>Please show workings .<br>

ivolga24 [154]

Answer:

see explanation

Step-by-step explanation:

Given f(x) then the derivative f'(x) is

f'(x) = lim(h tends to 0 ) $\frac{f(x+h)-f(x)}{h}$

= lim ( h to 0 ) $\frac{4(x+h)^2-2-(4x^2-2)}{h}$

= lim ( h to 0 ) $\frac{4(x+h)^2-2-4x^2+2}{h}$

= lim( h to 0 ) $\frac{4x^2+8hx+4h^2-4x^2}{h}$

= lim( h to 0 ) $\frac{8hx+4h^2}{h}$

= lim ( h to 0 ) $\frac{4h(2x+h)}{h}$ ← cancel h on numerator/ denominator

= lim ( h to 0 ) 4(2x + h) ← let h go to zero

f'(x) = 8x

5 0

2 years ago

Samia created the following tables of values for a linear system. She concluded that there is no

DaniilM [7]

Answer:

Step-by-step explanation:

3 0

3 years ago