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Kaylis [27]
4 years ago
13

What is the sample space for the probability model?

Mathematics
2 answers:
Sonja [21]4 years ago
7 0

Answer:

sample space for a probability model is the set of all possible outcomes

muminat4 years ago
3 0
Sample space for the probability model is the set of all possible outcomes. ❤️
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Mrs. Chauvet has an unfair number cube that lands with 6 facing up 40% of the time. Let X = the number of times that she rolls a
goldfiish [28.3K]

Answer:

P(X<1) = .216         P(X</=1) = .648

Step-by-step explanation:

its right

5 0
3 years ago
Pls answer bb I give extra pp-oints (::
DENIUS [597]

Answer:let me know please

Step-by-step explanation:

4 0
3 years ago
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PLEASE HELP ASAPPP !! Instructions: State what additional information is required in order to know that the triangles are congru
Svetllana [295]
<h3>Answer: angle T = angle W</h3>

Explanation:

We are given the sides are congruent due to the tickmarks. Specifically

TU = WV (single tickmarks)

TV = WX (double tickmarks)

So we just need the "A" of "SAS". The A is between the two S letters, so the angle is between the two sides. For triangle TUV, the angle T is between the two sides with the tickmarks. Similarly, angle W is between the tickmarked sides of triangle WVX.

If we know that angle T = angle W, then we have enough information to use SAS.

5 0
4 years ago
17,22,36,55,61,79 what is the median
Lunna [17]

Median is the middle number. To find median, the numbers must be ordered from least to greatest. The numbers are already ordered.

17,22,36,55,61,79

The middle numbers are 36 and 55, with 2 numbers on each side.

a, b, c, d, e, f

Add the 2 numbers and divide by 2

36 + 55 = 91

Now divide by 2

91 \div 2 = 45.5

The median is 45.5

6 0
3 years ago
Read 2 more answers
12. Find the area lying above the x - axis and below the parabolic curve y = 4x - x2.
Margarita [4]
First we find the zeroes so we don't take the integral of negative bits

4x-x²
x(4-x)
zeroes at x=0 and x=4
it opens down
so the part we are interested in is the bit between x=0 and x=4

\int\limits^4_0 {4x-x^2} \, dx =[2x^2- \frac{1}{3}x^3]^4_0=(32- \frac{64}{3})-(0)=  10.6666666666 or aout 10 and 2/3

C is answer
6 0
3 years ago
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