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VLD [36.1K]
3 years ago
14

GCF of 3y^2- 21y+ 36

Mathematics
1 answer:
stira [4]3 years ago
3 0

Answer:

3

Step-by-step explanation:

Find the GCF for the numerical part : 3, -21 , 36

find the GCF for the variable part y^2 , y^1

Multiply the values together

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Step-by-step explanation:

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Answer:

x = 10\sqrt{3}

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

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Laura created a website to create T-shirts. In the first month she put up her website she had only a single T-shirt order. Each
kiruha [24]

Laura received 144 orders over the first year

<em><u>Solution:</u></em>

<em><u>Given function is:</u></em>

f(n) = 2n - 1

Where, "n" is the month

In the first month she put up her website she had only a single T-shirt order

f(1) = 2(1) - 1 = 2 - 1

f(1) = 1

There are 12 months in a year

For the second month, and third month and so on, substitute n = 2, 3 and so on

f(2) = 2(2) - 1 = 4 - 1 = 3

f(3) = 2(3) - 1 = 6 - 1 = 5

f(4) = 2(4) - 1 = 8 - 1 = 7

f(5) = 2(5) - 1 = 10 - 1 = 9

f(6) = 2(6) - 1 = 12 - 1 = 11

f(7) = 2(7) - 1 = 14 - 1 = 13

f(8) = 2(8) - 1 = 16 - 1 = 15

f(9) = 2(9) - 1 = 18 - 1 = 17

f(10) = 2(10) - 1 = 20 - 1 = 19

f(11) = 2(11) - 1 = 22 - 1 = 21

f(12) = 2(12) - 1 = 24 - 1 = 23

<em><u>Thus total orders received over first year:</u></em>

Total orders = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23

Total orders = 144

Thus she received 144 orders over the first year

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