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svetoff [14.1K]
3 years ago
9

Jenny,eric and Boris sent a total of 79 text messages during the weekend Jenny sent 6 fewer messages than Erica Boris sent 3 tim

es as many messages as Eric how many messages did they each send?
Mathematics
1 answer:
inna [77]3 years ago
8 0
Lets say that J is for Jennys messages, B is for Boris’ and E is for Erics (or Ericas?).

79 = J + B + E

J = E - 6
B = 3E

Since both Jenny’s and Boris’ number of text messages has some kind of relation to Eric’s number of messages, we can say that:

79 = E - 6 (Jenny) + 3E (Boris) + E (Eric), so:

79 = E - 6 + 3E + E /combine like terms
79 = 5E - 6 /add 6 to both sides
79 + 6 = 5E /switch sides + combine like terms
5E = 85 /divide both sides by 5
E = 85/5
E = 17

So, Eric sent 17 messages. Lets get back to those equations we made for Jenny and Boris:

J = E - 6 = 17 - 6 = 11
B = 3E = 3 * 17 = 51

And we can check if it adds up: 51 + 11 + 17 = 79, which is what we were supposed to get.
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What is the volume of the prism? A rectangular prism with cubic units arranged in five rows of four. Each cubic unit is one cubi
vodka [1.7K]

Answer:

D. 80 cubic inches

Step-by-step explanation:

Arranged in five rows of four => we can say the length, depth and width as 5,4,4

So, the volume is equal to 5 x 4 x 4 = 80 cubic inches

Sorry that this answer might not make sense to you, I just can't think of any better explanation.

3 0
2 years ago
Consider randomly selecting a student at a certain university, and let A denote the event that the selected individual
Stells [14]

Answer:

(a) P( A ∩ B )=0.5 is not possible.

(b) 0.7

(c) 0.3

(d) 0.3

(e) 0.4

Step-by-step explanation:

Given information: The alphabet A and B represents the following events

A : Individual has a Visa credit card.

B: Individual has a MasterCard.

P(A)= 0.6 and P(B)=0.4.

(a)

We need to check whether P( A ∩ B ) can be 0.5 or not.

A\cap B\subset A and A\cap B\subset B

P(A\cap B)\leq P(A) and P(A\cap B)\leq P(B)

P(A\cap B)\leq 0.6 and P(A\cap B)\leq 0.4

From these two inequalities we conclude that

P(A\cap B)\leq 0.4

Therefore, P( A ∩ B )=0.5 is not possible.

(b)

Let P(A\cap B)=0.3

We need to find the probability that student has one of these two types of cards.

P(A\cup B)=P(A)+P(B)-P(A\cap B)

Substitute the given values.

P(A\cup B)=0.6+0.4-0.3=0.7

Therefore the probability that student has one of these two types of cards is 0.7.

(c)

We need to find the probability that the selected student has neither type of card.

P(A'\cup B')=1-P(A\cup B)

P(A'\cup B')=1-0.7=0.3

Therefore the probability that the selected student has neither type of card is 0.3.

(d)

The event that the select student has a visa card, but not a mastercard is defined as

A-B

It can also written as

A\cap B'

The probability of this event is

P(A\cap B')=P(A)-P(A\cap B)

P(A\cap B')=0.6-0.3=0.3

Therefore the probability that the select student has a visa card, but not a mastercard is 0.3.

(e)

We need to find the probability that the selected student has exactly one of the two types of cards.

P(A\cap B')+P(A\cap B')=P(A\cup B)-P(A\cap B)

P(A\cap B')+P(A\cap B')=0.7-0.3

P(A\cap B')+P(A\cap B')=0.4

Therefore the probability that the selected student has exactly one of the two types of cards is 0.4.

8 0
3 years ago
Evaluate 9.5v + 8.9w when v=6 and w=7
Anton [14]

Answer:119.3

Step-by-step explanation:

9.5*6=57

8.9*7=62.3

57+62.3=119.3

7 0
3 years ago
What is the approximate volume of a cylinder with a diameter of 4 cm and height of 10 cm? A: 125.6 B: 251.3 C:502.7 D:1005.3
frutty [35]
Your answer will be c there you go buddy
5 0
3 years ago
Logan has 20 action figures. He is shipping them to a friend. He can fit 3 action figures in a box. How many boxes will he need
nasty-shy [4]
He will need seven boxes
5 0
3 years ago
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