Let the price of a ticket be originally T dollars, and the number of clients be N.
let the price decrease by x 3-dollars.
"there is an average increase of 4 people for every $3 decrease on the price of the ticket."
means:
if the price is decreased by 1-3$:
then N become N+4, and T becomes T-3
if the price is decreased by 2-3$:
then N become N+4+4=N+2*4, and T becomes T-3-3=T-2*3
So if the price is decrease by x-3 dollars:
N becomes N+4x, and T becomes T-3x
"A circus owner sells an average of 340 tickets when the price of a ticket is $75."
In this case N=340, and T=75$
If the owner does not change the price ticket, x=0, the revenue is 340*75,
If the owner decreases the price of the tickets by x-3$, then the revenue will be
(N+4x)(T-3x)=(340+4x)(75-3x) dollars,
If R is the function of the revenue depending on x, then
R(x)=(340+4x)(75-3x) dollars
Answer: R(x)=(340+4x)(75-3x) dollars
1463 (1064 divided by 8= 133, 133x11)
Answer: 16
Step-by-step explanation:
multiplying by negative exponents can be a little tricky. So (1/4x)^-2 becomes 16/x^2 = __/x^2 so the missing number is 16
Answer:
40 girls
Step-by-step explanation:
if there r 32 than u know 8 times 4 equals 32. Then u have to multiply 4 on the other side as well. So 10 times 4 equals 40 girls
Answer:
The answer is D, 80$ for three 1 hour lessons. I hope this helps :D
