Answer:
4c + 15
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION BELOW;
A department store's customer parking lot has 4 rows with an equal number of parking spots in each row. The lot also has 15 parking spots for store employees. If c cars can be parked in each of the 4 main rows of the parking lot, what is the expression for the maximum number of cars that can be parked in the parking lot?
15c − 4
c(15 − 4)
4c + 15
4(c + 15)
✓We were told that the customer stores parking has Total number of 4 rows,
✓ for " c" cars to be parked in the 4 main rows i.e in each of them, we can calculate the overall numbers of car parked in the rolls as ( 4 × c)= 4c
✓ we were told that there are 15 parking spots available to employees in the store
✓ maximum number of cars that can fit into the parking lot will be ( 15 + 4c)
= 4c + 15
At death means x= 0, so on the graph you can see that (0, 500), so 500 carbon atoms are present at death.
Plug 11,240 in for t in the equation, and you are left with N(t) = 500(1/2)^2 = 125 carbon atoms.
See the graph point (25,000, 24.298)? That means that after 25,000 years 24.298 carbon atoms will be present. So the answer is 25,000 years.
Answer:
Where's the number line?
Step-by-step explanation:
Answer:
I only know number 5 so here it is
the solution for the left is: 2x6=12
the solution for the right is: 5x3+4x1=15+4=19
and the answers are: 1.12 . 2.19
Answer:
146
Step-by-step explanation:
arrange your values in descending order then cancel out last value with the first value.
the middle value would be your answer.
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