The solution of the given equation is -6 and 1.
<h3>What is Quadratic Equation?</h3>
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.
Here, given equation:
(x+2)(x+3) = 12
x(x+3)+2(x+3) = 12
x² + 3x + 2x + 6 = 12
x² + 5x + 6 - 12 = 0
x² + 5x - 6 = 0
x² + 6x - x - 6 = 0
x(x+6) -1(x+6) = 0
(x+6)(x-1) = 0
Now, x + 6 = 0 or x - 1 = 0
x = -6 or x = 1
Thus, the solution of the given equation is -6 and 1.
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Answer:
−30a−6
Step-by-step explanation:
Let's simplify step-by-step.
−9a−10−6a+7−9a−10−6a+7
=−9a+−10+−6a+7+−9a+−10+−6a+7
Combine Like Terms:
=−9a+−10+−6a+7+−9a+−10+−6a+7
=(−9a+−6a+−9a+−6a)+(−10+7+−10+7)
=−30a+−6
BRAINLIEST. if you don't mind.
(16*0) + (4*1)
16*10 = 160
4*1 = 4
160 + 4
The answer is 164! :)
Finding y intercept and x intercept is easy:
X intercept will be of the form (x,0) and y intercept will be of the form (0,y)
● If you put x=0 in the equation, you will get y-intercept.
● If you put y=0 in the equation, you will get x-intercept.
______________________________
Given equation: 2x - 4y = 10
◆ Put x = 0
2×0 - 4y = 10
=> -4y = 10
=> y = 10/(-4)
=> y = -5/2
Thus y intercept is (0, -5/2)
◆Put y = 0
2x - 4×0 = 10
=> 2x = 10
=> x = 10/2
=> x = 5
Thus the x intercept is (5,0)
