All categories

2 years ago

Which shows the correct substitution of the values a, b, and c from the equation 1 = -2x + 3x² + 1 into the quadratic

1 answer:

8 0

The coefficient 'a' for the quadratic term is a = 3
The coefficient 'b' for the linear term is b = -2
The coefficient 'c' is 0
Step-by-step explanation :
The given expression is,

To solve this problem we are using quadratic formula.
The general quadratic equation is,

Formula used :

Now we a have to solve the above equation and we get the value of 'x'.

a = 3, b = -2, c = 0

The coefficient 'a' for the quadratic term is a = 3
The coefficient 'b' for the linear term is b = -2
The coefficient 'c' is 0

You might be interested in

The formula v= u+ atdescribes connections between u: starting velocity a: acceleration t: time v: final velocity a)In a particul

Bess [88]

Answer:

49 = 0 +9.8t
t = 5

Step-by-step explanation:

It usually works to follow directions.

a) Substitute the numbers into the formula:

v = u + at

49 = 0 +9.8t

b) Solve the equation:

49/9.8 = t = 5 . . . . . divide by the coefficient of t

6 0

3 years ago

Find the new amount of the original amount is 45 grams and the percent of decrease is 36%.

Semenov [28]

Answer:

28.8

Step-by-step explanation:

the original is 45=100%

it reduced by 36% meaning;100%-36%=64%

if45=100%

? =64%

45*64=2880/100=28.8

6 0

3 years ago

Elsa scores eight points in six minutes if she could send years at this rate how many points will she score 9 minutes

Minchanka [31]

Answer:

12 points

Step-by-step explanation:

9 is 1.5 times 6, so 8 times 1.5 gives you the answer of 12 points.

5 0

3 years ago

Please solve this<br><img src="https://tex.z-dn.net/?f=%20%7Cx%20%5E%7B2%7D%20%2B%203x%20-%201%20%7C%20%20%3C%203" id="TexFormul

klasskru [66]

$\bf |x^2+3x-1|\ \textless \ 3\implies 
\begin{cases}
+(x^2+3x-1)\ \textless \ 3\\\\
-(x^2+3x-1)\ \textless \ 3
\end{cases}\\\\
-------------------------------\\\\
x^2+3x-1\ \textless \ 3\implies x^2+3x-4\ \textless \ 0\implies (x+4)(x-1)\ \textless \ 0
\\\\\\
x\ \textless \ 
\begin{cases}
-4\\
1
\end{cases}\\\\
-------------------------------\\\\
-(x^2+3x-1)\ \textless \ 3\implies x^2+3x-1\boxed{\ \textgreater \ }-3
\\\\\\
x^2+3+2\ \textgreater \ 0\implies (x+2)(x+1)\ \textgreater \ 0\implies x\ \textgreater \ 
\begin{cases}
-2\\
-1
\end{cases}$

8 0

3 years ago

Read the image for instructions

Gwar [14]

Answer:

4 ther are 4 line symmetery

8 0

2 years ago

Read 2 more answers