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RUDIKE [14]
3 years ago
13

Use the Distributive Property on 45x-6

Mathematics
1 answer:
Alexandra [31]3 years ago
5 0

Answer:

<h3>180</h3>

Step-by-step explanation:

<h3>45 × -6 = 45 × [10+(-6)]</h3><h3>45 × (10-6)</h3><h3>45 × 4</h3><h3>180</h3>
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The graph of y=f(x) is a transformation of the graph y=h(x) write a formula for the function f in terms of function h
Marat540 [252]

Answer:

y=h(x)-8

Step-by-step explanation:

it shifted down 8 units

7 0
3 years ago
QUESTION IS DOW BELOW 5 POINTS EACH PLEASE HELP PLEASE HELP PLEASE HELP
sveticcg [70]

a. Central angle in the circle is: Angle BAC

b. A major arc is: Arc BEC

c. A minor arc is: Arc BC

d. m(arc BEC) = 260°.

e. m(arc BC) = 100°.

<h3>What is the Central Angle Theorem?</h3>

The central angle theorem states that: the central angle measure of a circle equals the measure of the intercepted arc.

<h3>What is a Central Angle?</h3>

A central angle is formed by two radii of a circle, and the vertex of the angle is at the center of the circle.

<h3>What is a Major Arc?</h3>

Any arc that is more than half a circle (semicircle) or has a measure that is greater than 180 degrees, is referred to as a major arc of that circle. The measure of the major arc > 180 degrees.

<h3>What is a Minor Arc?</h3>

Any arc that is not more than half a circle (semicircle) or has a measure that is less than 180 degrees, is referred to as a minor arc of that circle. The measure of the minor arc < 180 degrees.

a. One central angle that can be identified in circle A is: Angle BAC

b. A major arc that can be identified in circle A is: Arc BEC

c. A minor arc that can be identified in circle A is: Arc BC.

d. According to the central angle theorem, we have:

m(arc BEC) = 360 - 100

m(arc BEC) = 260°

e. We are given that m(angle BAC) = 100°, therefore, according to the central angle theorem, we have:

m(arc BC) = m(angle BAC )

m(arc BC) = 100°

Learn more about major and minor arcs on:

brainly.com/question/16289520

#SPJ1

3 0
2 years ago
The water level in a lake changed by -28 centimeters in 7 days. The water level changed by the same amount each day. How much di
denis-greek [22]

Answer:

in 7 days level of water changed in lake= -28

the water level change each day= -28/7= -4cm

Step-by-step explanation:

7 0
3 years ago
I have 7 hundreds blocks, 5 tens block's, and 8 one's blocks. I use my blocks to model two 3-digit numbers. What could my two nu
Margaret [11]
758, 758.0
I think....................
3 0
3 years ago
Please answer the question below (ABOUT VECTORS AND MAGNITUDE)
coldgirl [10]

(a) <em>v</em> appears to have a fixed direction along the positive <em>x</em>-axis. If ||<em>u</em>|| = 150 N, ||<em>v</em>|| = 220 N, then when <em>θ</em> = 30°, you have

<em>u</em> = (150 N) (cos(30°) <em>i</em> + sin(30°) <em>j</em> ) ≈ (129.904 <em>i</em> + 75 <em>j</em> ) N

<em>v</em> = (220 N) (cos(0°) <em>i</em> + sin(0°) <em>j</em> ) = (220 <em>i</em> ) N

(<em>i</em> and <em>j</em> are the unit vectors in the positive <em>x</em> and <em>y</em> directions)

and their sum is

<em>u</em> + <em>v</em> ≈ (349.904 <em>i</em> + 75 <em>j</em> ) N

with magnitude

||<em>u</em> + <em>v</em>|| ≈ √((349.904)² + (75)²) N ≈ 357.851 N ≈ 357.9 N

and at angle <em>φ</em> made with the positive <em>x</em>-axis such that

tan(<em>φ</em>) ≈ (75 N) / (349.904 N)   →   <em>φ</em> ≈ 12.098° ≈ 12.1°

(b) Letting <em>θ</em> vary from 0° to 180° would make <em>v</em> a function of <em>θ</em> :

<em>u</em> = (150 N) (cos(<em>θ</em>) <em>i</em> + sin(<em>θ</em>) <em>j</em> ) = (150 cos(<em>θ</em>) <em>i</em> + 150 sin(<em>θ</em>) <em>j</em> ) N

Then

<em>u</em> + <em>v</em> = ((220 + 150 cos(<em>θ</em>)) <em>i</em> + (150 sin(<em>θ</em>)) <em>j</em> ) N

→   <em>M</em> = ||<em>u</em> + <em>v</em>|| = √((220 + 150 cos(<em>θ</em>))² + (150 sin(<em>θ</em>))²) N

<em>M</em> = √(48,400 + 66,000 cos(<em>θ</em>) + 22,500 cos²(<em>θ</em>) + 22,500 sin²(<em>θ</em>)) N

<em>M</em> = 10 √(709 + 660 cos(<em>θ</em>)) N

(c) As a function of <em>θ</em>, <em>u</em> + <em>v</em> makes an angle <em>α</em> with the positive <em>x</em>-axis such that

tan(<em>α</em>) = (150 sin(<em>θ</em>) / (220 + 150 cos(<em>θ</em>))

→   <em>α</em> = tan⁻¹((15 sin(<em>θ</em>) / (22 + 15 cos(<em>θ</em>)))

(d) Filling in the table is just a matter of evaluating <em>M</em> and <em>α</em> for each of the given angles <em>θ</em>. For example, when <em>θ</em> = 0°,

<em>M</em> = 10 √(709 + 660 cos(0°)) N = 370 N

<em>α</em> = tan⁻¹((15 sin(0°) / (22 + 15 cos(0°))) = 0°

When <em>θ</em> = 30°, you get the same result as in part (a).

When <em>θ</em> = 60°,

<em>M</em> = 10 √(709 + 660 cos(60°)) N ≈ 323.3 N

<em>α</em> = tan⁻¹((15 sin(60°) / (22 + 15 cos(60°))) = 23.8°

and so on.

4 0
3 years ago
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