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3 years ago

How to add subtract multiply and divide fractions?

1 answer:

3 0

Add and subtract: Find Least Common Denominator, multiply out, add/subtract as normal

Multiply: Multiply both top and bottom

Divide: Multiply by reciprocal

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0.6 (n+10)=3.6 What's the answer

Anika [276]

The answer is -4+x. I had an explanation but bro just threw it out cause I wouldn't get him a pencil

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4 years ago

Read 2 more answers

3-5(3a+6)3-5(3a+6) in standard form

WARRIOR [948]

Answer:

$-15a-27$

Step-by-step explanation:

Given

$3-5(3a+6)$

Required

Express in standard form

$3-5(3a+6)$

Start by opening bracket

$3-5*3a-5*6$

$3-15a-30$

Collect Like Terms

$-15a-30+3$

$-15a-27$

Hence;

The standard form of $3-5(3a+6)$ is $-15a-27$

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3 years ago

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3 years ago

Give two ways to z-7 algebraic expression in words

Alja [10]

Answer:

z minus seven.

z took away from seven.

Step-by-step explanation:

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4 years ago

Based on information from a large insurance company, 67% of all damage liability claims are made by single people under the age

svetoff [14.1K]

Answer:

We conclude that the insurance claims of single people under the age of 25 is higher than the national percent reported by the large insurance company.

Step-by-step explanation:

We are given that based on information from a large insurance company, 67% of all damage liability claims are made by single people under the age of 25.

A random sample of 52 claims showed that 43 were made by single people under the age of 25.

Let p = population proportion of claims made by single people

So, Null Hypothesis, $H_0$ : p $\leq$ 67% {means that the insurance claims of single people under the age of 25 is smaller than or equal to the national percent reported by the large insurance company}

Alternate Hypothesis, $H_A$ : p > 67% {means that the insurance claims of single people under the age of 25 is higher than the national percent reported by the large insurance company}

The test statistics that will be used here is One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of claims made by single people under the age of 25 = $\frac{43}{52}$ = 0.83

n = sample of claims = 52

So, the test statistics = $\frac{0.83-0.67}{\sqrt{\frac{0.67(1-0.67)}{52} } }$

= 2.454

The value of z-test statistics is 2.454.

Since in the question, we are not given the level of significance so we assume it to be 5%. Now, at 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 2.454 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the insurance claims of single people under the age of 25 is higher than the national percent reported by the large insurance company.

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4 years ago