How to add subtract multiply and divide fractions?

ipn [44]

The price of Ravi's lunch, before tax and tip was added to the total cost of the meal is $13.19.

<h3>What is the price of the lunch?</h3>

Both the tax and the tip paid would increase the cost of the meal. Thus, their dollar value has to be subtracted from the total amount he pays.

Value of the lunch after the tip has been removed = (1 - 0.2) x 17.92 = $14.34

Value of the lunch after the tax has been removed = (1 - 0.08) x $14.34 = $13.19

To learn more about taxes, please check: brainly.com/question/25311567

#SPJ1

5 0

2 years ago

What is the value of x? assume that the line is tangent to the circle

nekit [7.7K]

Answer:

70°

Step-by-step explanation:

Connect the center of the circle with endpoints of the chord. Let the center of the circle be point O and endpoints of the chord be points A (let point A lie on the tangent line too)and B.

From the figure, central angle AOB has the measure of 220°.

Consider triangle AOB. This triangle is isosceles triangle because OA and OB are both radii. In this triangle the measure of angle AOB is 360° - 220° = 140°.

Angles OAB and OBA are angles adjacent to the base AB, so they are congruent. The sum of the measures of all interior angles in triangle is always 180°, so

m∠OAB + m∠OBA + m∠AOB = 180°

m∠OAB = m∠OBA = 1/2 (180° - 140°)

m∠OAB = 20°

Since drawn line is tangent line, then OA is perpendicular to this tangent line and

x° = 90° - 20°

x° = 70°

4 0

3 years ago

A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.

zmey [24]

Answer:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X=2.2$ represent the sample mean

$s=0.29$ represent the sample standard deviation

$n=40$ sample size

$\mu_o =2.1$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2.1$

Alternative hypothesis: $\mu > 2.1$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=40-1=39$

Since is a one side test the p value would be:

$p_v =P(t_{(39)}>2.18)=0.0177$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

7 0

3 years ago

Harrison has 30 cds in his music collection. If 40% of the cds are country and 30% are pop, how many are other types of music

Pavel [41]

Well you have to find out how many cd is 40% and 30%
30% = 30x.3=9
40% = 30x.4=16
now add 16 and 9
16+9=25 now subtract 25 from 30 and see that you have 5 cd of a different type of music to find that as a % divide 5 by 35 to get .14 I rounded it to the nearest hundreth now move the decimal over 2 spots to get 14%

8 0

3 years ago

Read 2 more answers

Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol

aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

$P(A\cap B)=P(A)\times P(B)$

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

$=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09$

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

$P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018$

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

$P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118$

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0

3 years ago