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Alona [7]
3 years ago
5

The general form of the equation of a circle is x2+y2−4x−8y−5=0.

Mathematics
1 answer:
valentina_108 [34]3 years ago
4 0

Answer:

centre = (2, 4)

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² - 4x - 8y - 5 = 0

Rearrange the x/y terms together and add 5 to both sides

x² - 4x + y² - 8y = 5

Use the method of completing the square on both the x/y terms

add ( half the coefficient of the x/y terms )² to both sides

x² + 2(- 2)x + 4 + y² + 2(- 4)y + 16 = 5 + 4 + 16

(x - 2)² + (y - 4)² = 25 ← in standard form

with centre (2, 4) and r = \sqrt{25} = 5

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Solve the system
Helga [31]
The answer is actually choice A

---------------------------------------------------------
---------------------------------------------------------

If we add up the equations straight down we will have 0a+2b = 6

Note how adding the 'a' terms gives us 3a + (-3a) = 3a-3a = 0a. The 0a term is really 0 since 0 times anything is 0. So the 'a' terms will go away

The equation 0a+2b = 6 turns into 0+2b = 6 and that simplifies to 2b = 6

To isolate b, we divide both sides by 2

2b = 6
2b/2 = 6/2
b = 3

We can stop here since only one answer choice has b = 3, which is choice A. However, let's keep going to find the value of 'a'

Plug b = 3 into any equation with 'a' and 'b', then solve for 'a'

3a+4b = 9
3a+4*3 = 9
3a+12 = 9
3a+12-12 = 9-12
3a = -3
3a/3 = -3/3
a = -1

So a = -1 and b = 3 pair up to form (a,b) = (-1,3)

--------------------------------------

To check, plug this ordered pair back into both equations

Equation 1:
3a+4b = 9
3*(-1)+4*3 = 9
-3+12 = 9
9 = 9
Equation 1 has been checked out

Equation 2:
-3a-2b = -3
-3(-1)-2(3) = -3
3 - 6 = -3
-3 = -3
this is true as well

So this confirms that the final answer is choice A
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