Answer:
6) B. Reflection over the y-axis, then reflection over the x-axis
7) B. The initial value of the function is the y-intercept of the line, 275
8) A. y = 45 - 6x
Step-by-step explanation:
6) See first attached file :)
7) Option A is incorrect because the rate of change/slope is "-20x" not just "-20." Option C is incorrect because the initial value/y-intercept is $275 and not $2. Option D is incorrect because it implies she doesn't withdraw $20 the first month, which wasn't mentioned in the question. Option B is the only one to apply to the graph. See second attached file for graph reference.
8) The question explains the function "y=6x+45" and that matches all options except for option A.
haha third time for this one
Answer:
A. The height of the ball is the same after 1 second and 3 seconds.
Step-by-step explanation:
The quadratic equation function modeling is used to analyze the relationship between variables in the equation. If the ball is at height and t is time then the ball is on symmetric line which will move for initial 1 second then stabilizes at 3 seconds.
Answer:
27 + (-40) = -13
Step-by-step explanation:
27 + (-40)
= 27 - 40
= -13
Answer:
y +5 = -1/3(x -3)
Step-by-step explanation:
The slope of the given line is 3. The slope of the perpendicular line is the negative reciprocal of that, -1/3. Then the point-slope equation is ...
y -y1 = m(x -x1) . . . . line with slope m through point (x1, y1)
y -(-5) = -1/3(x -3)
y +5 = -1/3(x -3)
26.315789, you should use a caculator
