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Ahat [919]
3 years ago
10

Write each improper fraction as a mixed number

Mathematics
1 answer:
vazorg [7]3 years ago
7 0

Answer:

To write improper fractions as mixed numbers you need to do a few steps

Example: 19/3

To change this into a mixed number you want to take 19/3

19/3= 6.33333333 (it goes on forever)

to turn it into a fraction when you go

3*6=18

you subtract 18 from 19 to get 1

then you take the number that you are dividing by 3

and put that under your remainder

Your answer would be 6 1/3

Hope this helps ;)

Step-by-step explanation:

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Mrs. Cleaver mixes 1.24 liters of red paint with 3 times as much blue paint to make purple paint. She pours the paint equally in
otez555 [7]

The amount of blue paint in each container is \fbox{\begin\\\ 0.744 liters \end{minispace}}.

Further explanation:

The mixture mixed by Mrs. Cleaver contains 1.24 litres of red paint with 3 times blue paint to obtain purple paint.

So, the amount of blue paint is calculated as,

{3} \times {1.24}=3.72 \text { liters}

Therefore, the total amount of paint mixture is the sum of blue paint and red paint.

\fbox{\begin \\\begin{aligned} \text{Total paint}= 1.24+3.72\\=4.96 \text{ liters}\\\end{aligned}\\\end{minispace}}

Now, as Mrs. Cleaver divides the paint mixture equally in 5 containers so the amount of paint in one container is calculated as,

\boxed{\begin{aligned}\text{Amount of paint in one container}&= \dfrac{4.96}{5}\\ &=0.992 \text{ liters} \end {aligned}}

Since amount of blue paint mixed is three times the red paint so the fraction of blue paint to the total paint is \dfrac{3}{4}.  

Now, as it is known that the fraction of blue paint to the total paint is \dfrac{3}{4} and the amount of paint in a container is 0.992 \text{ liters} then the blue paint in one container is calculated as,

\boxed{\begin{aligned}\text{Blue paint in one container} =\dfrac{3}{4} \times 0.992\\=0.248 \text{ liters}\end{aligned}}

Thus, the amount of blue paint in each of the five containers is \fbox{\begin\\\ 0.744 liters \end{minispace}}.

Learn more:  

1. To solve one variable linear equation brainly.com/question/1682776

2. Linear equation application brainly.com/question/2479097

3. Composite functions brainly.com/question/2142762

Answer details  

Grade: Middle school  

Subject: Mathematics  

Chapter: Mixtures and ratios

Keywords: mixture, paint, red paint, blue paint, Mrs. Cleaver, purple paint, fraction, each container, five containers, divides, times, equally divide, mixes, liters.

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85 is the correct answer.
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Write an equation of the line that passes through the given point and is parallel to the given line.
Margaret [11]

Answer:

Part 40) y=-2x+9

Part 41) y=5x+6

Part 42) y=\frac{2}{3}x+\frac{4}{3}

Step-by-step explanation:

Remember that

If two lines are parallel, then their slopes are the same

Part 40) Write an equation of the line that passes through the given point

and is parallel to the given line

we have

Point (4,1)

Given line y=-2x+7

step 1

Find the slope of the given line

The given line is a equation of the line in slope intercept form

y=mx+b

where

m is the slope

b is the y-intercept

so

The slope of the given line is

m=-2

step 2

Find the y-intercept b

we have

m=-2

(4,1)

substitute in the linear equation

1=(-2)4+b

solve for b

b=1+8

b=9

step 3

Find equation of the line that passes through the given point and is parallel to the given line

we have

m=-2

b=9

substitute

The equation of the line is

y=-2x+9

Part 41) Write an equation of the line that passes through the given point

and is parallel to the given line

we have

Point (0,6)

Given line y=5x-3

step 1

Find the slope of the given line

The given line is a equation of the line in slope intercept form

y=mx+b

where

m is the slope

b is the y-intercept

so

The slope of the given line is

m=5

step 2

Find the y-intercept b

b=6 ----> because the y-intercept is the point (0,6) (value of y when the value of x is equal to zero)

step 3

Find equation of the line that passes through the given point and is parallel to the given line

we have

m=5

b=6

substitute in the linear equation

y=5x+6

Part 42) Write an equation of the line that passes through the given point

and is parallel to the given line

we have

Point (-5,-2)

Given line y=(2/3)x+1

step 1

Find the slope of the given line

The given line is a equation of the line in slope intercept form

y=mx+b

where

m is the slope

b is the y-intercept

so

The slope of the given line is

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step 2

Find the y-intercept b

we have

m=\frac{2}{3}

(-5,-2)

substitute in the linear equation

-2=(\frac{2}{3})(-5)+b

solve for b

-2=-\frac{10}{3}+b

b=-2+\frac{10}{3}

b=\frac{4}{3}

step 3

Find equation of the line that passes through the given point and is parallel to the given line

we have

m=\frac{2}{3}

b=\frac{4}{3}

substitute

The equation of the line is

y=\frac{2}{3}x+\frac{4}{3}

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Answer:

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Step-by-step explanation:

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