Solution (1)
for k=0 / for k=1 / for k=-1
x=0 / x=2π / x=-2π
acc / acc / rej
solution (2)
for k=0 / for k=1 / for k=-1
x=0 / x=2π/3 / x=-2π/3
acc / acc / rej
Note that i'm trying values of K which make the answer belong to our interval;
So our solution which i will represent as a set is;
S € {0,2π/3,2π}
If by 4x(2) you mean 4x to the power 2 or 4x^2...it can be solved in the following way
f(x)=4x^2-4x-3
=4x^2+2x-6x-3
=2x(2x+2)-3(2x+2)
=(2x-3)(2x+2)
Therefore x=3/2 or x=-2/2=(-1)
5 pounds = $2.49
1 pound = $2.49 ÷ 5 = $0.50 (nearest hundredth)
.
Answer: $0.50/pound
A slope of any line parallel to y = x + 2 will be 1.
The slope of parallel lines are always equal. Since we do not see a number next to the x in the original equation, there is an assumed 1 there. Therefore any line that is parallel with it would also have to be 1.
10) V=πr² *h= π*10²*12≈3770
11) V=A(base)*h= (3√3/2)*(9²)*10=2104
A(base)=(P*a)/2=(6*9*3√3)/2=9*9*3√3/2
12)V=πr² *h=π*18² *6≈6107
13)V=4*3*12=144
14) h(triangle)=√(5²-3²)=√16=4
A(base)=(3*4)/2=6
V=A(base)* height (prism)=6*2=12
15) V=A(base)*h= (3√3/2)*(6²)*11= 1029
16)V=A(base)*h=2(1+√2)5²*22≈2656
