Question

Suppose that the New England Colonials baseball team is equally likely to win a game as not to win it. If Colonials games are chosen at random, what is the probability that exactly of those games are won by the Colonials

Answer 1

Answer:

Suppose that the New England Colonials baseball team is equally likely to win a game as not to win it. If 5 Colonials games are chosen at random, what is the probability that exactly 4 of those games are won by the Colonials?

The probability that exactly 4 of those games are won by the Colonials would be 0.375

Step-by-step explanation:

The probability can be obtained using the binomial formula, step by step explanation is contained in the attachment;

Answer 2

Answer: 0.375

Step-by-step explanation:

Each of the games picked can be a w (win) or a l (lose), the chances are equal.

All that could happen in 4 picked games can happen in 6 ways:

(w,w,l,l)(w,l,w,l)(w,l,l,w)(l,w,w,l)(l,w,l,w)(l,l,w,w)

Hence:

P(2w,2l)=6/16=3/8 =0.375