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ValentinkaMS [17]
4 years ago
6

I need help with all of them thanks

Mathematics
2 answers:
igomit [66]4 years ago
6 0
N-13= 63
N-7= 73
<span>8+N=17-10
</span><span>17+N=80
</span><span>N+25=50-11
</span><span>N-18=74
</span><span>N+6=82
</span><span>N+3=77
</span><span>8N=72
</span><span>2N=15+9
</span>
KiRa [710]4 years ago
3 0
1. s-13=63       76
2. m-7=73        80
3. 8+m=17-10     0
4. 17+m=80       63
5. Q+25=50-11    14
6. n-18=74       92
7. n+6=82        76
8. n+3=77        74
9. 8x=72         9
10. 2x=15+9      12
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To decrease the impact on the environment, factory chimneys must be high enough to allow pollutants to dissipate over a larger a
Komok [63]

Answer:

The probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the height of chimneys in factories.

The mean height is, <em>μ</em> = 100 meters.

The standard deviation of heights is, <em>σ</em> = 12 meters.

It is provided that a random sample of <em>n</em> = 40 chimney heights is obtained.

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

Since the sample selected is quite large, i.e. <em>n</em> = 40 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean heights of chimneys.

\bar X\sim N(\mu_{\bar x},\ \sigma^{2}_{\bar x})

Compute the probability hat the sample mean height for the 40 chimneys is greater than 102 meters as follows:

P(\bar X>102)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}})>\frac{102-100}{12/\sqrt{40}})

                    =P(Z>1.05)\\=1-P(Z

*Use a <em>z</em>-table fr the probability.

Thus, the probability hat the sample mean height for the 40 chimneys is greater than 102 meters is 0.1469.

8 0
3 years ago
Simplify if possible
Anarel [89]
The answer is the last choice 2 1/2
8 0
3 years ago
Read 2 more answers
PLZ HELP URGENT GET THE BRAINLIEST AND MORE POINTS
lord [1]

Answer:

  • The 27th term is 22

Step-by-step explanation:

Let the first term is a and common difference is d.

<u>The nth term is:</u>

  • aₙ = a + (n - 1)d

<u>We have:</u>

  • a₆ = 15
  • a₉ = 16

<u>The difference of these terms is:</u>

  • (a + 8d) - (a + 5d) = 16 - 15
  • 3d = 1
  • d = 1/3

<u>Then the first term is:</u>

  • a + 5*1/3 = 15
  • a = 15 - 5/3 = 13 1/3

<u>The nth term equation is:</u>

  • aₙ = 13 1/3 + 1/3(n - 1) = 1/3n + 13

<u>If the nth term is 22, find n:</u>

  • 1/3n + 13 = 22
  • 1/3n = 22 - 13
  • 1/3n = 9
  • n = 9*3
  • n = 27
7 0
3 years ago
eight wooden spheres with radii 3 in. are packed snugly into a square box 12 in. on one side. the remaining space is filled with
ZanzabumX [31]
Vbox-vspheres

vbox=, I assume we are dealing with l=w=h
so
v=lwh=12^3=1728

vsphere=(4/3)pir^3
r=3
vsphere=(4/3)pi3^3=4pi9=36pi
8 of them so
8 times 36pi=288pi or about 904.7786842338604526772412943845 cubic inches



vbox-sphere=1728-904.7786842338604526772412943845=823.2213157661395473227587056155
space filled by packing beads is about 823.22 cubic inches
beads percent is 823.2213157661395473227587056155/1728 times 100=47.64% filled by beads






3 0
3 years ago
PLEase hurry please hURyy plaese hurry
steposvetlana [31]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

All these answers are correct. I triple - checked!

Step-by-step explanation:

In order from questions asked top - to - bottom:

First question:

  • 23 businesses

Second question:

  • 18 businesses

Third question:

  • 14 businesses

Fourth question:

  • 6 businesses

I hope this helps!

- sincerelynini

6 0
3 years ago
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