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2 years ago

4. IN YOUR OWN WORDS How can you find the area of a composite figure?

1 answer:

5 0

The given area of any composite figure can be subdivided into triangles, rectangles, squares, trapezoids and lastly semi circle and with the given question calculate their areas and combine them together.

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Help 15 points!!!!!!!!!!!!!!!!!!!!!

Svetllana [295]

Answer:

see explanation

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan A = $\frac{opposite}{adjacent}$ = $\frac{BC}{AC}$ = $\frac{7}{8}$ , then

∠ A = $tan^{-1}$ ( $\frac{7}{8}$ ) ≈ 41° ( to the nearest degree )

The sum of the angles in the triangle = 180° , then

∠ B + 41° + 90° = 180°

∠ B + 131° = 180° ( subtract 131° from both sides )

∠ B = 49°

Using Pythagoras' identity in the right triangle

AB² = BC² + AC² = 7² + 8² = 49 + 64 = 113 ( take square root of both sides )

AB = $\sqrt{113}$ ≈ 10.6 ( to the nearest tenth )

3 0

3 years ago

This is what I meant on my last question. sorry

Zigmanuir [339]

Answer:

its C

Step-by-step explanation:

4 0

3 years ago

Val needs to find the area enclosed by the figure. The figure is made by attaching semicircles to each side of a 42-m-42-m squar

oee [108]

The area enclosed by the figure is 4533.48 square meters.

<u>Step-by-step explanation:</u>

Side length of the square = 42m

The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.

Radius of the semicircle = 21m

Area of the square = 42 x 42 = 1764 square meters

Area of 1 semicircle = π(21 x 21) /2

= (3.14) (441) /2

= 1384.74/2

= 692.37 square meters

Area of 4 semicircle = 4 x 692.37

= 2769.48 square meters

Total area = 1764 + 2769.48

= 4533.48 square meters

The area enclosed by the figure is 4533.48 square meters.

7 0

3 years ago

Accuracy in taking orders at a drive-through window is important for fast-food chains. Periodically, QSR Magazine publishes "The

pav-90 [236]

Answer:

a) 0.7412 = 74.12% probability that all the three orders will be filled correctly.

b) 0.0009 = 0.09% probability that none of the three will be filled correctly

c) 0.0245 = 2.45% probability that at least one of the three will be filled correctly.

d) 0.9991 = 99.91% probability that at least one of the three will be filled correctly

e) 0.0082 = 0.82% probability that only your order will be filled correctly

Step-by-step explanation:

For each order, there are only two possible outcomes. Either it is filled correctly, or it is not. Orders are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The percentage of orders filled correctly at Burger King was approximately 90.5%.

This means that $p = 0.905$

You and 2 friends:

So 3 people in total, which means that $n = 3$

a. What is the probability that all the three orders will be filled correctly?

This is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{3,3}.(0.905)^{3}.(0.095)^{0} = 0.7412$

0.7412 = 74.12% probability that all the three orders will be filled correctly.

b. What is the probability that none of the three will be filled correctly?

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.905)^{0}.(0.095)^{3} = 0.0009$

0.0009 = 0.09% probability that none of the three will be filled correctly.

c. What is the probability that one of the three will be filled correctly?

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{3,1}.(0.905)^{1}.(0.095)^{2} = 0.0245$

0.0245 = 2.45% probability that at least one of the three will be filled correctly.

d. What is the probability that at least one of the three will be filled correctly?

This is

$P(X \geq 1) = 1 - P(X = 0)$

With what we found in b:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0009 = 0.9991$

0.9991 = 99.91% probability that at least one of the three will be filled correctly.

e. What is the probability that only your order will be filled correctly?

Yours correctly with 90.5% probability, the other 2 wrong, each with 9.5% probability. So

$p = 0.905*0.095*0.095 = 0.0082$

0.0082 = 0.82% probability that only your order will be filled correctly

7 0

3 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Temka [501]

Answer:

It diverges.

Step-by-step explanation:

We are given the inetegral: $\int\limits^{\infty}_2 \frac{1}{x} (\ln x)^2 dx$

$\int\limits^{\infty}_2 \frac{1}{x} (\ln x)^2 dx=\int\limits^{\infty}_2 (\ln x)^2 d(\ln x)=\\\\=\lim_{t \to \infty} \int\limits^t_2 (\ln x)^2d(\ln x)=\lim_{t \to \infty} \frac{(\ln t)^3}{3} |^t_2=\infty-\frac{(\ln 2)^3}{3} =\infty$

So it is divergent.

7 0

4 years ago