Answer:
{(–4, 2), ( –2, 1), (2, 0), (4, 5)}
Step-by-step explanation: Look at the first number in each bracket for domain :)
We have been given a table of data that represents the distances traveled by three bicycle riders and time spent on their rides.
To find sum of distances traveled by three riders at the same rate, we will have to find unit rate at which each rider is cycling.
![\text{Rate at which Marta is cycling}=\frac{8\text{ miles}}{80\text{ minutes}}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20at%20which%20Marta%20is%20cycling%7D%3D%5Cfrac%7B8%5Ctext%7B%20miles%7D%7D%7B80%5Ctext%7B%20minutes%7D%7D)
![\text{Rate at which Marta is cycling}=0.1\frac{\text{ miles}}{\text{ minute}}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20at%20which%20Marta%20is%20cycling%7D%3D0.1%5Cfrac%7B%5Ctext%7B%20miles%7D%7D%7B%5Ctext%7B%20minute%7D%7D)
Let us find Loribeth's unit rate of cycling.
![\text{Rate at which Loribeth is cycling}=\frac{6\text{ miles}}{42\text{ minutes}}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20at%20which%20Loribeth%20is%20cycling%7D%3D%5Cfrac%7B6%5Ctext%7B%20miles%7D%7D%7B42%5Ctext%7B%20minutes%7D%7D)
![\text{Rate at which Loribeth is cycling}=0.1428571428571429\frac{\text{ miles}}{\text{ minute}}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20at%20which%20Loribeth%20is%20cycling%7D%3D0.1428571428571429%5Cfrac%7B%5Ctext%7B%20miles%7D%7D%7B%5Ctext%7B%20minute%7D%7D)
Let us find Ira's unit rate of cycling.
![\text{Rate at which Ira is cycling}=\frac{15\text{ miles}}{75\text{ minutes}}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20at%20which%20Ira%20is%20cycling%7D%3D%5Cfrac%7B15%5Ctext%7B%20miles%7D%7D%7B75%5Ctext%7B%20minutes%7D%7D)
![\text{Rate at which Ira is cycling}=0.2\frac{\text{ miles}}{\text{ minute}}](https://tex.z-dn.net/?f=%5Ctext%7BRate%20at%20which%20Ira%20is%20cycling%7D%3D0.2%5Cfrac%7B%5Ctext%7B%20miles%7D%7D%7B%5Ctext%7B%20minute%7D%7D)
Let us convert 3.5 hours in minutes.
3.5 hours = 3 hours+50 minutes=(3*60+50) minutes =230 minutes.
Now let us add rates of our three cycles and then multiply the sum by 230 minutes to find distance traveled by three riders altogether.
![\text{Distance traveled by three riders altogether}=230\cdot(0.1+0.2+0.1428571428571429)](https://tex.z-dn.net/?f=%5Ctext%7BDistance%20traveled%20by%20three%20riders%20altogether%7D%3D230%5Ccdot%280.1%2B0.2%2B0.1428571428571429%29)
![\text{Distance traveled by three riders altogether}=230\cdot(0.4428571428571429)](https://tex.z-dn.net/?f=%5Ctext%7BDistance%20traveled%20by%20three%20riders%20altogether%7D%3D230%5Ccdot%280.4428571428571429%29)
![\text{Distance traveled by three riders altogether}=101.857](https://tex.z-dn.net/?f=%5Ctext%7BDistance%20traveled%20by%20three%20riders%20altogether%7D%3D101.857)
Therefore, three riders will travel 101.857 miles while travelling altogether.
Answer:
no, 90 days after september 5 is december 4
Step-by-step explanation:
Answer:
Hilda bought 11.83 lb of pork
Step-by-step explanation:
Hope this helps <3
Answer:2
The 0 in the tens place as well as the 0 in the hundredths place are both place holders. We know this because they are surrounded on both sides by no-zero numbers.
As far as NUMERICAL form goes, it is already done. 906.903 can be considered numerical form.