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lorasvet [3.4K]
3 years ago
13

WILL GIVE BRAINLIESTTT!!!! PLS HELP

Mathematics
1 answer:
Kaylis [27]3 years ago
4 0
7/30 x 100 = approx 23.3%
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30 points + brainliest answer.<br> Answer D got cut off, it is 5/18.
Basile [38]

C. 5/6

30 people with soda + 45 people with lemonade = 75/90 people

simplifies to 5/6.


3 0
3 years ago
i am a solid figure with two congruent polygons that are bases,connected with lateral face that are rectangles.
BabaBlast [244]
Rectangular prisim is the answer
6 0
3 years ago
Consider the sets below. u = {x | x is a real number} a = {x | x is an odd integer} r = {x | x = 3, 7, 11, 27} is r ⊂ a?
-BARSIC- [3]

The correct option is (B) yes because all the elements of set R are in set A.

<h3>What is an element?</h3>
  • In mathematics, an element (or member) of a set is any of the distinct things that belong to that set.

Given sets:

  1. U = {x | x is a real number}
  2. A = {x | x is an odd integer}
  3. R = {x | x = 3, 7, 11, 27}

So,

  • A = 1, 3, 5, 7, 9, 11... are the elements of set A.
  • R ⊂ A can be understood as R being a subset of A, i.e. all of R's elements can be found in A.
  • Because all of the elements of R are odd integers and can be found in A, R ⊂ A is TRUE.

Therefore, the correct option is (B) yes because all the elements of set R are in set A.

Know more about sets here:

brainly.com/question/2166579

#SPJ4

The complete question is given below:
Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A?

(A) yes, because all the elements of set A are in set R

(B) yes, because all the elements of set R are in set A

(C) no because each element in set A is not represented in set R

(D) no, because each element in set R is not represented in set A

8 0
1 year ago
Assume the time required to complete a product is normally distributed with a mean 3.2 hours and standard deviation .4 hours. Ho
Alex787 [66]

Answer: 3.712 hours or more

Step-by-step explanation:

Let X be the random variable that denotes the time required to complete a product.

X is normally distributed.

X\sim N(\mu=3.2\text{ hours},\ \sigma=0.4\text{ hours} )

Let x be the times it takes to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

Then, P(\dfrac{X-\mu}{\sigma}>\dfrac{x-\mu}{\sigma})=0.10

P(z>\dfrac{x-3.2}{\sigma})=0.10\ \ \ [z=\dfrac{x-\mu}{\sigma}]

As, P(z>1.28)=0.10  [By z-table]

Then,

\dfrac{x-3.2}{0.4}=1.28\\\\\Rightarrow\ x=0.4\times1.28+3.2\\\\\Rightarrow\ x=3.712

So, it will take 3.712 hours or more to complete a random unit in order to be in the top 10% (right tail) of the time distribution.

3 0
4 years ago
slader Suppose that 8% of all bicycle racers use steroids, that a bicyclist who uses steroids tests positive for steroids 96% of
d1i1m1o1n [39]

Answer:

P = 0.4812

Step-by-step explanation:

First, we need to use here two expressions and then do the calculations.

The first one is the conditional probability which is:

P(B|A) = P(A∩B)/P(A)   (1)

The second expression to use has relation with the Bayes's theorem which is the following:

P(D|C) = P(C|D)*P(D) / P(C|D)*P(D) + P(C|d)*P(d)   (2)

Now, the expression (2) is the one that we will use to calculate the probability of a selected random bicyclist who tests positive for steroids.

So, in this case, we will call C for positive and D that is using steroids and d is the opposite of d, which means do not use steroids.

Then, the probabilities are the following:

P(D) = 8% or 0.08

P(C|D) = 96% or 0.96

P(C|d) = 9% or 0.09

P(d) = 1 - 0.08 = 0.92

With these data, let's replace in expression 2

P(D|C) = 0.96 * 0.08 /0.96 * 0.08 + 0.09*0.92

P(D|C) = 0.0768 / 0.1596

P(D|C) = 0.4812 or 48.12%

8 0
3 years ago
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