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nekit [7.7K]
3 years ago
6

What is the solution to the following equation?

Mathematics
2 answers:
Rasek [7]3 years ago
4 0
2(3x - 7) + 18 = 10

Subtract 18 from both sides:

2(3x - 7) = -8

divide both sides by 2

3x - 7 = -4

add 7 to both sides


3x = 3


divide both sides by 3:


x = 1


So your answer is A) 1
olga2289 [7]3 years ago
3 0
2(3x - 7) + 18 = 10
Subtract 18 from both sides.
2(3x - 7) = -8
Distribute the side with parenthesis.
2(3x) + 2(-7) = -8
6x -14 = -8
Add 14 to both sides.
6x = 6
Divide both sides by 6.
x = 1

I hope this helps!
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3 years ago
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3 years ago
If two of these shapes are randomly chosen, one after the other without replacement, what is the probability that the first will
aleksandrvk [35]

Answer:

P(T\ n\ S) = \frac{1}{14}

Step-by-step explanation:

*Missing Part of the Question*

4 stars

5 triangles

3 circles

3 squares

Required

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Total = 4 + 5 + 3 + 3

Total = 15

Represent the triangle with T and square with S

So, we're solving for P(T n S)

P(T\ n\ S) = P(T) * P(S)

Solving for P(T)

P(T) = \frac{n(T)}{Total}

P(T) = \frac{5}{15}

Solving for P(S)

The question implies a probability without replacement;

Hence Total has now been reduced by 1

Total = 14

P(S) = \frac{n(S)}{Total}

P(S) = \frac{3}{14}

Recall that

P(T\ n\ S) = P(T) * P(S)

P(T\ n\ S) = \frac{5}{15} * \frac{3}{14}

P(T\ n\ S) = \frac{15}{15 * 14}

P(T\ n\ S) = \frac{1}{14}

Hence, the required probability is

P(T\ n\ S) = \frac{1}{14}

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3 years ago
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Answer:

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Hope this helps!! Have a wonderful day :3

3 0
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