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3 years ago

What is the solution to the following equation?

2 answers:

4 0

2(3x - 7) + 18 = 10

Subtract 18 from both sides:

2(3x - 7) = -8

divide both sides by 2

3x - 7 = -4

add 7 to both sides

3x = 3

divide both sides by 3:

x = 1

So your answer is A) 1

olga2289 [7]3 years ago

3 0

2(3x - 7) + 18 = 10
Subtract 18 from both sides.
2(3x - 7) = -8
Distribute the side with parenthesis.
2(3x) + 2(-7) = -8
6x -14 = -8
Add 14 to both sides.
6x = 6
Divide both sides by 6.
x = 1

I hope this helps!

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Benito is selling T-shirts for $8 each for his school fund-raiser. So far, he has sold 16 T-shirts. How many more does he need t

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D. When you do the math, the results to everything should be t=9. D is the only outlier. Therefore, D is the answer in this case.

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4 years ago

Using the function f(x) = 2x + 7 find the following: (show your work) f(2) f(7)

denpristay [2]

Replace the x with 2: f(2)=2*2+7=4+7=11
replace the x with 7: f(7)=2*7+7=14+7=21

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3 years ago

Read 2 more answers

When investigating times required for drive-through service, the following results (in seconds) were obtained: Restaurant A 120

iris [78.8K]

Answer:

Step-by-step explanation:

Restaurant A data in ascending order : 67 68 72 89 96 97 120 124

Restaurant B data in ascending order : 49 56 76 78 95 98 115 126

Restaurant A

Mean = $\frac{67+68+72+89+96+97+120+124}{8}$ = 91.625
Median = Since there are even number of observations so,

= $\frac{4^{th}obs + 5^{th}obs }{2}$ = $\frac{89+96}{2}$ = 92.5

Mid range = $\frac{Highest Value-Lowest Value}{2}$ = $\frac{124-67}{2}$ = 28.5
Range = Highest value - Lowest value = 124 - 67 = 57
Variance = $\frac{\sum (X_i - \mu )^{2}}{N-1}$ ,where Xi are sample values and $\mu$ is mean

Solving above equation we get, variance = 493.982

Standard Deviation = $\sqrt{variance}$ = 22.226

Restaurant B

Mean = $\frac{49+56+76+78+95+98+115+126}{8}$ = 74.375

Median = Since there are even number of observations so,

= $\frac{4^{th}obs + 5^{th}obs }{2}$ = $\frac{78+95}{2}$ = 86.5

Mid Range = $\frac{Highest Value-Lowest Value}{2}$ = $\frac{126-49}{2}$ = 38.5

Range = Highest value - Lowest value = 126 - 49 = 77

Variance = $\frac{\sum (X_i - \mu )^{2}}{N-1}$ ,where Xi are sample values and $\mu$ is mean

= 727.982

Standard Deviation = $\sqrt{variance}$ = 26.981

Now comparing the results of two restaurants we conclude that:

Restaurant A on an average takes more time for drive-through service than Restaurant B.
Median time for Restaurant A is also more than Restaurant B.
Restaurant B has more variation in time taken for drive through service as the variance & standard deviation of Restaurant B is more than A.
There is more spread in the time data for Restaurant B as it has more range than A.

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4 years ago

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Step-by-step explanation:

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3 years ago

The equation for the cost in dollars of producing computer chips is y =.000015x^2-.03x+35. Where x is the number of chips produc

Anna35 [415]

In order to find the number of chips that would result in the minimum cost, we take the first derivative of the given equation. Note that the derivative refers to the slope of the graph at a given point. We can utilize this concept knowing that at the minimum or maximum point of a graph, the slope is zero.

Taking the derivative of the given equation and equating it to zero, we have:

y' = (0.000015)(2)x - (0.03)x° + 0
0 = (0.00003)x - 0.03

Solving for x or the number of chips produced, we have x = 1000. We then substitute this value in the given equation, such that,

y = (0.000015)(1000)² - (0.03)(1000) + 35

The minimized cost, y, to produce 1000 chips is then calculated to be $20.

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3 years ago