Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
Answer:
I think X is just the subtraction of the other angles
Step-by-step explanation:
x=95-57
X=38°
Step-by-step explanation:
1snack pack cost 1.6dollars($0. 6+$1)
10snack pack cost 16dollars.
($0. 6+$1)×10 =/ unequal $9
Answer:
(x − 1)² + (y + 1)² = 18
Step-by-step explanation:
Equation of a circle is:
(x − h)² + (y − k)² = r²
where (h, k) is the center and r is the radius.
The center is (1, -1), so plugging that in:
(x − 1)² + (y + 1)² = r²
A point on the circle is (4, 2), so plugging that in:
(4 − 1)² + (2 + 1)² = r²
18 = r²
Therefore, the equation is:
(x − 1)² + (y + 1)² = 18
Answer:
C
Step-by-step explanation:
Slope of a line that goes trough the points (x1=9, y1=1) and (x2=17, y2=2)
m= (y2-y1)/(x2-x1) = (2-1) / (17-9) = 1/8
