Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
Answer:
dont see sphere
Step-by-step explanation:
Answer:
4th box
Step-by-step explanation:
Answer:
17.73205081
Step-by-step explanation:
Didn't use a calculator :) Please mark me as brainliest. Thanks!
First, we need to understand the speed formula:
The time used = distance ÷ rate
In this case, the time needed would be:
5 1/5 ÷ 2 1/6
= (5×5+1)/5 ÷ (2×6+1)/6
=26/5 ÷ 13/6
When there is division in an equaiton, we can swap the nominator and denominator of the fraction amd change it to multiplication:
=26/5 × 6/13
= (13 x 2)/5 x 6/(13 x 1)
Factorize 26 and 13,we get:
=2/5 x 6/1
= 12/5 ft or 2.4 ft
Therefore the answer is 12/5ft or 2.4ft.
Hope it helps!