Answer:
What does it mean to talk about the ' volume ' of the rectangular box or cylindrical container
---------
It's how much it will hold, in cubic units.
It's a 3-dimensional value.
It's not restricted to rectangular boxes or cylinders
Answer : The correct option is, (A) ![54\pi cm^3](https://tex.z-dn.net/?f=54%5Cpi%20cm%5E3)
Step-by-step explanation :
First we have to calculate the volume of cylinder.
Formula used:
Volume of cylinder = ![\pi r^2h](https://tex.z-dn.net/?f=%5Cpi%20r%5E2h)
where,
r = radius = 3 cm
h = height = 18 cm (We are assuming that 3 solid spheres stacked to each other = 3 × diameter of each sphere = 3 × 2 × 3 = 18)
Volume of cylinder = ![\pi (3cm)^2\times (18cm)](https://tex.z-dn.net/?f=%5Cpi%20%283cm%29%5E2%5Ctimes%20%2818cm%29)
Volume of cylinder = ![162\pi cm^3](https://tex.z-dn.net/?f=162%5Cpi%20cm%5E3)
Now we have to calculate the volume of 3 solid spheres.
Formula used:
Volume of 3 spheres = ![3\times \frac{4}{3}\pi r^3](https://tex.z-dn.net/?f=3%5Ctimes%20%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E3)
Volume of 3 spheres = ![4\pi r^3](https://tex.z-dn.net/?f=4%5Cpi%20r%5E3)
Volume of 3 spheres = ![4\pi (3)^3](https://tex.z-dn.net/?f=4%5Cpi%20%283%29%5E3)
Volume of 3 spheres = ![108\pi cm^3](https://tex.z-dn.net/?f=108%5Cpi%20cm%5E3)
Now we have to calculate the amount of empty space within a cylinder.
Amount of empty space within a cylinder = Volume of cylinder - Volume of 3 spheres
Amount of empty space within a cylinder = ![162\pi cm^3-108\pi cm^3](https://tex.z-dn.net/?f=162%5Cpi%20cm%5E3-108%5Cpi%20cm%5E3)
Amount of empty space within a cylinder = ![54\pi cm^3](https://tex.z-dn.net/?f=54%5Cpi%20cm%5E3)
Therefore, the amount of empty space within a cylinder is, ![54\pi cm^3](https://tex.z-dn.net/?f=54%5Cpi%20cm%5E3)
First of all, you have to understand
![g](https://tex.z-dn.net/?f=g)
<span> is a square-root function.
</span>Square-root functions are continuous across their entire domain, and their domain is all real x-<span>values for which the expression within the square-root is non-negative.
</span>
In other words, for any square-root function
![q](https://tex.z-dn.net/?f=q)
and any input
![c](https://tex.z-dn.net/?f=c)
in the domain of
![q](https://tex.z-dn.net/?f=q)
(except for its endpoint), we know that this equality holds:
Let's take
![\sqrt{x}](https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20)
<span>as an example.
</span>
The domain of
![\sqrt x](https://tex.z-dn.net/?f=%5Csqrt%20x)
is all real numbers such that
![x \geq 0](https://tex.z-dn.net/?f=x%20%5Cgeq%200)
. Since
![x=0](https://tex.z-dn.net/?f=x%3D0)
is the endpoint of the domain, the two-sided limit at that point doesn't exist (you can't approach
![0](https://tex.z-dn.net/?f=0)
<span>from the left).
</span>
<span>However, continuity at an endpoint only demands that the one-sided limit is equal to the function's value:
</span>
In conclusion, the equality
![lim \ q(x)=q(c)](https://tex.z-dn.net/?f=lim%20%5C%20q%28x%29%3Dq%28c%29)
holds for any square-root function
![q](https://tex.z-dn.net/?f=q)
and any real number
![c](https://tex.z-dn.net/?f=c)
in the domain of
![q](https://tex.z-dn.net/?f=q)
e<span>xcept for its endpoint, where the two-sided limit should be replaced with a one-sided limit. </span>
The input
![x=-3](https://tex.z-dn.net/?f=x%3D-3)
, is within the domain of
![g](https://tex.z-dn.net/?f=g)
<span>.
</span>
Therefore, in order to find
![lim \ g(x)](https://tex.z-dn.net/?f=lim%20%5C%20g%28x%29%20)
we can simply evaluate
![g](https://tex.z-dn.net/?f=g)
at
![x-3](https://tex.z-dn.net/?f=x-3)
<span>.
</span>