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erastovalidia [21]
3 years ago
14

7x(15+5) plz help me solve this question by formula BODMAS

Mathematics
1 answer:
kupik [55]3 years ago
7 0

The brackets are first, then the multiplication

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For what values of x is the expression below defined??<br> Square root of 2-x
PIT_PIT [208]
I don't know, Sorry, but I will keep looking at it to see if I can figure it out, Sorry

7 0
3 years ago
1/2 x + 2 = 1/6 x - 1 =
aksik [14]

Step-by-step explanation:

1/2x+2−1/6x=1/6x−1−1/6x

1/3x+2=−1

1/3x+2−2=−1−2

1/3x=−3

3*(1/3x)=(3)*(−3)

x=−9 <- ANSWER

3 0
3 years ago
A square has a perimeter of 36 ft. What is the length of each side?
Yanka [14]
9 ft is the answer because a square has four sides, so 36 divided by 4 is 9
3 0
3 years ago
You throw a ball up and its height h can be tracked using the equation h=2x^2-12x+20.
postnew [5]

<em><u>This problem seems to be wrong because no minimum point was found and no point of landing exists</u></em>

Answer:

1) There is no maximum height

2) The ball will never land

Step-by-step explanation:

<u>Derivatives</u>

Sometimes we need to find the maximum or minimum value of a function in a given interval. The derivative is a very handy tool for this task. We only have to compute the first derivative f' and have it equal to 0. That will give us the critical points.

Then, compute the second derivative f'' and evaluate the critical points in there. The criteria establish that

If f''(a) is positive, then x=a is a minimum

If f''(a) is negative, then x=a is a maximum

1)

The function provided in the question is

h(x)=2x^2-12x+20

Let's find the first derivative

h'(x)=4x-12

solving h'=0:

4x-12=0

x=3

Computing h''

h''(x)=4

It means that no matter the value of x, the second derivative is always positive, so x=3 is a minimum. The function doesn't have a local maximum or the ball will never reach a maximum height

2)

To find when will the ball land, we set h=0

2x^2-12x+20=0

Simplifying by 2

x^2-6x+10=0

Completing squares

x^2-6x+9+10-9=0

Factoring and rearranging

(x-3)^2=-1

There is no real value of x to solve the above equation, so the ball will never land.

This problem seems to be wrong because no minimum point was found and no point of landing exists

3 0
3 years ago
A new photocopier works 4 times as fast as an old one. When the machines work together, a university can produce all its staff m
Usimov [2.4K]

The old photocopier can make x manuals in an hour. The new photocopier can make 4x. Combined, they made 5x manuals in an hour.

In one hour they can make 1/28 of the manuals.

1/(28*5)=1/140 is the rate.

The new photocopier can make all the manuals in 4/140 or 35 hours.

The old one can make them in 140 hours.

6 0
2 years ago
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