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gtnhenbr [62]
3 years ago
7

Find the product -1/2 y(2y3-8)

Mathematics
1 answer:
MissTica3 years ago
8 0
0-(( \frac{1}{2} *y)*2y^3-8) \\ \\ then \ we \ would \ simplify \ 1/2 \\ \\ we \ factor y^3 - 4 \\ \\ 4 \ would \ not \ be \ a \ perfect \ cube. \\ \\ therefore, \ your \ answer \ would \ then \ be \ the \ following: \\ \\ \boxed{ -y * (y^3 - 4)}
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Answer:

y =3x - 12

Step-by-step explanation:

I'm fairly certain this is the answer.

Consider the point (3,-3). In terms of variables this is written (x,y).

Remember that the equation for slope is y = mx + b.

In that equation, "b" is your y-intercept, and "m" is your slope.

If 2 lines are parallel, they have the same slope but different y-intercepts. So you can use the slope from the equation y=3x-4 to find the parallel line. You can also plug in the values 3 and -3 to solve for b, our y-intercept.

If we set up the equation, we have -3 = 3(3) + b.

Now solve for b.

-3 = 9 + b

Combine like terms, so that -12 = b, and you have your y-intercept.

To create the equation, take out the coordinate pair that the line passes through, and only have the SLOPE and the Y-INTERCEPT showing in the equation.

Therefore, y = 3x - 12

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3 years ago
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Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
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