Answer:
f(-3) = 16
Step-by-step explanation:
Given:
f(x) = 2x² + x + 1
Required:
f(-3)
Solution:
Substitute x = -3 into f(x) = 2x² + x + 1
f(-3) = 2(-3)² + (-3) + 1
f(-3) = 2*9 - 3 + 1
f(-3) = 18 - 3 + 1
f(-3) = 16
Answer:
.
Step-by-step explanation:
Answer: y = (-3x/2) + 1
Step-by-step explanation:
From the standard equation y = mx + c, the slope of the equation is 2/3. Therefor slope of a line perpendicular to it will be -3/2.
Hence the equation will be
y = (-3x/2) + c
As this line passes through (-2,4), putting these values in this equation gives c = 1.
Hence the answer is y = (-3x/2) + 1
Answer:
Step-by-step explanation:
We can answer this in two ways: Differentiation and Graphing.
<u>Differentitate:</u>
The first derivative of a function yields a function that provides the slope for any point on the line of the original function. The slope of a vertex is zero, so we can set the first derivative to 0 and solve for x.
f(x) = 3(x-1)^2 + 4
f(x) = 3(x-1)(x-1) + 4
f(x) = 3(x^2 - 2x + 1) + 4
f(x) = 3x^2 - 6x + 7
f'(x) = 6x -6
Set this = 0 and find x:
0 = 6x -6
x = 1
The value of y when x=1 in the original equation is:
f(1) = 3(1-1)^2 + 4
y = 4
The vertex is (1,4)
<u>Graph:</u>
You can use DESMOS to plot the function. The result is attached. Look for the vertex and read the coordinates. (1,4) seems to work.