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mr Goodwill [35]
3 years ago
13

How do you write 30% into a decimal to the nearest hundredth

Mathematics
2 answers:
Feliz [49]3 years ago
8 0
0.3
Move that decimal to the left two times! By the way, 0.3 and 0.30 are the same exact thing you know that.
omeli [17]3 years ago
7 0
.30 move the decimal two times to the left.

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Please help! I’m stuck on this question. I’m very confused.
Gala2k [10]
C= -3 and d=15

I took the 'c' term out of the left side
c multiplied by 4x makes -12x so c must be -3
that means that -3 multiplied by -5 equals d (which is 15)

7 0
3 years ago
Damian has a spinner. He spun the arrow 60 times and it landed on green 12 times.
professor190 [17]

Answer:

it would be 2

Step-by-step explanation:

what you do to find the probability is to divide so you divide 60 from 12 which automatically = 5 so then you divide 10 from 5 which gives you 2

6 0
3 years ago
The difference of two numbers is 3 and their quotinet is 2 what are the 2 numbers
blsea [12.9K]
The two numbers are 6 and 3
3 0
3 years ago
Solve the simultaneous equations C^2+d^2=5 and 3c+4d=2
Naily [24]
If 3c+4d=2 then c=(2-4d)/3
And if you put that into the other equation
{\frac{2 - 4d}{3}}^{2}  +  {d}^{2}  = 5
Then you multiply everything by 3, getting

{(2 - 4d)}^{2}  + 3 {d}^{2}  = 15
And then

2 - 4d +  \sqrt{3} d =  \sqrt{15}
Leaving
d( \sqrt{3}  - 4) =  \sqrt{15}  - 2
I dont have a calc with me right now but you just pot this into the calculator:
d =  \frac{ \sqrt{15} - 2 }{ \sqrt{3}  - 4}
And when you get the number you insert it into the nest eqation to get c

c =  \frac{2 - 4d}{3}
So basically

c =  \frac{2 - 4 \frac{ \sqrt{15}  - 2}{ \sqrt{3}  - 4} }{3}







6 0
3 years ago
Read 2 more answers
It is believed that students who begin studying for final exams a week before the test score differently than students who wait
olga55 [171]

Answer:

H0 : μ1 = μ2

H0 : μ1 < μ2

Step-by-step explanation:

Given :

Early studiers, group 1, mean μ1

Late studiers, group 2 ; mean, μ2

To test the claim that students who study earlier have an average score that is less than the average score for students

The null hypothesis ; there is no difference in average score

H0 : μ1 = μ2

Alternative hypothesis is early studiers means is less than average score of late studiers

H0 : μ1 < μ2

7 0
3 years ago
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