Just replace x with 0
y=0+3
y=3
and then 1
y=1+3
y=4
and then 2
y=2+3
y=5
and so on
the numerical pattern looks like this:
3 , 4 , 5 , 6 , 7 , 8 , 9.....
Function a is linear, the equation is y = 5/3x or y=5/3x+0
Answer:
How high is the climber?
Step-by-step explanation:
So, he starts at 1200. And then he walks 800 times 3, which is 2100.
So, 2100 + 1200 = 3300
1.) 70x/100x^2 = 7/10x
2.) 16x^3/24x = 2x^2/3
3.) 7x(2x+1)/21(2x+1) = x/3
4.) 35x - 35/x^2 - 1 = 35/x + 1
5.) x + 7/x^2 + 4x - 21 = 1/x - 3
6.) x^2 - 6x + 5 = x - 5/5
7.) x^2 - 36/x^2 - 3x - 18 = x + 6/x + 3
8.) x^2 - 3x - 10/x^2 + x - 2 = x - 5/x - 1
B is the answer to your problem
