Selection B is appropriate.
_____
The signs of the coefficients tell you the binomial factors must have both signs positive (selections B and C only). Selection B produces an x-term that is 15x+15x=30x (as we want); selection C produces an x-term that is 45x+5x=50x (not what we want).
Answer:
4m+4
4(m+1)
Step-by-step explanation:
2m+m+m +2+2
Combine like terms
4m+4
Factor out 4
4(m+1)
Answer:
Step-by-step explanation:
to compare them, we need to convert them into like fractions
4/3 and 5/2
lcm of 3 and 2 is 6
4/3 × 2/2 = 8/6
5/2 × 3/3 = 15/6
15/6 is greater than 8/6
<em><u>so 5/2 is greater than 4/3</u></em>
similarly,
-3/2 and -4/5
we need to convert them into like fractions
lcm of 2 and 5 is 10
-3/2 × 5/5 = -15/10
-4/5 × 2/2 = -8/10
-8/10 is greater than -15/10
<u><em>so -4/5 is greater than -3/2</em></u>
Hope this helps
plz mark as brainliest!!!!
You would use the distributive property.
Answer:
(130.08, 139.92)
Step-by-step explanation:
Given that:
Mean (m) = 135
Standard deviation (σ) = 30
Sample size (n) = 100
α = 90%
The confidence interval value is obtained using the relation:
Mean ± Zcritical * (standard deviation / sqrt(n))
Zcritical at 90% = 1.64
standard deviation / sqrt(n) = 30 / sqrt(100)
= 30 / 10 = 3
Hence,
135 ± 1.64 * (3)
Lower limit : 135 - (1.64 * 3) = 130.08
Upper limit : 135 + (1.64 * 3) = 139.92
Hence,
Confidence interval = (130.08, 139.92)
