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e-lub [12.9K]
3 years ago
14

1. Define: (1) factor (ii) multiple. Give five examples of each.it​

Mathematics
1 answer:
sineoko [7]3 years ago
5 0

Answer:

A factor is a number that when its multiplied with another number, gives a product of a given number. Example: The factors of 21 are 7,3,1 and 21. A multiple is a number that can be divided by another number a certain amount of times evenly (without a remainder). Example: Some multiples of 4 are: 8, 12, 16, and 20.

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Let x represent the number of pages left to be read in a book consisting of 780 pages.
tamaranim1 [39]

Answer:

E.

Step-by-step explanation:

not sure sorry...anyone help this

8 0
3 years ago
How do I solve this
Veronika [31]

Answer:

P(A or B) = 1.16

Step-by-step explanation:

Given probability:

Probability of event A = P(A) = 0.46

Probability of event B = P(B) = 0.7

P(A and B) = 0.43

Find:

P(A or B)

Computation:

If A is an incident and B is a separate event, P(A or B) is the possibility of either A, B, or both events occurring.

P(A or B) = P(A) + P(B)

P(A or B) = 0.46 + 0.7

P(A or B) = 1.16

5 0
3 years ago
Plzzzzzzzzzzzzzzz<br> aaaaaaaaaaaaaaaaaaaaa
kvasek [131]

Answer:

C. 7x + 11

Step-by-step explanation:

(13x-4)+(-6x+15)

13x-4-6x+15

7x+11

4 0
3 years ago
Read 2 more answers
steve has quiz scores of 60,64,75,71. If all the quizzes count the same, what is the lowest grade he can make on the next quiz t
NeX [460]

Answer:

The last quiz score must be at least an 80 to get the average to be a 70.

Step-by-step explanation:

In order to find this, you need to take the average of the 4 test scores along with the unknown test score (x). So, to find an average, we add all the numbers together and divide by the amount of tests taken. We can then set this equal to 70 since that is the minimum average.

(60 + 64 + 75 + 71 + x)/5 = 70 ------> Multiply both sides by 5

(60 + 64 + 75 + 71 + x) = 350 -----> Combine like terms

270 + x = 350 -----> Subtract 270 from both sides

x = 80

7 0
3 years ago
A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
laiz [17]

<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


6 0
3 years ago
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