There are no common factors between the two terms
13
x
and
10
- see explanation below.
Explanation:
First, we can try factoring the constants in each term:
13 is a prime number and therefore can only be factored to 1 and 13.
10 can be factored as (1 x 10) or (2 x 5).
Because there are no common factors other than
1
the constants cannot be factored.
And, because there is no
x
in the second term (10), we cannot factor an
x
out of the two terms.
Therefore this expression cannot be factored.
Answer:
188.49
Step-by-step explanation:
use the diameter to find the circumference..
C = d pi or C = 2r pi
when you plug in 20, you get 62.83
now take that, and multiply it by 3, because the wheels went around three times.
62.83 * 3 = 188.49 inches
i hope this was helpful to you!
stay safe!!
:)
Answer:
1.8611 x 10^4 lbs per capita
Step-by-step explanation:
To calculate the per capita garbage we have to divide the amount of garbage by the number of people
garbage = 5.416 x 10^12 lbs
people = 2.91 x 10^8
5.416 x 10^12 / 2.91 x 10^8 =
To make it easier we can take the scientific notation of the first term to the same exponent the second
5.416 x 10^12 = 54,160 x 10^8
54,160 x 10^8 / 2.91 x 10^8 =
Now that we have multiplying the same in both parts of the division you can simplify both terms above and below
54,160/2.91 = 18,611
18,611 = 1.8611 x 10^4
Answer: u.(v+w) = -20
Step-by-step explanation:
Given;
u = -i+j
v = 10i-2j
w = -8j
v+w = 10i-2j +(-8j)
v+w = 10i-10j
u .(v+w) = (-i+j).(10i-10j)
= -1×10 + 1 ×-10
= -10-10
u.(v+w) = -20
Answer:
-0.861,0.195
Step-by-step explanation:
Population proportion = the proportion reported by the Govt. for adolescents do not do enough aerobic physical activity to meet the guidelines for youth.
= 0.80
Sample size = 149
Sample favourable =115
Sample proportion = ![\frac{115}{149} =0.7718](https://tex.z-dn.net/?f=%5Cfrac%7B115%7D%7B149%7D%20%3D0.7718)
![q=1-p = 0.2282\\](https://tex.z-dn.net/?f=q%3D1-p%20%3D%200.2282%5C%5C)
![H_0: p = 0.80\\H_a: p](https://tex.z-dn.net/?f=H_0%3A%20p%20%3D%200.80%5C%5CH_a%3A%20p%3C0.80)
(left tailed test at 5% significance level)
If H0 is true, std error = ![\sqrt{\frac{0.8*0.2}{149} } =0.033](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B0.8%2A0.2%7D%7B149%7D%20%7D%20%3D0.033)
a) Z statistic = p diff/std error
=![\frac{0.7718-0.80}{0.033} \\=-0.861](https://tex.z-dn.net/?f=%5Cfrac%7B0.7718-0.80%7D%7B0.033%7D%20%5C%5C%3D%3Cstrong%3E-0.861%3C%2Fstrong%3E)
b) p value = 0.195